Impius Posted June 21, 2006 Share Posted June 21, 2006 Greetings. I've just started to learn PHP and I need some help with a script, what I'm looking for is a script that will display an image if accessed by a specific IP address and an alternate image if accessed by any other IP. If any one could assist me in locating or writting a script that would preform those actions it would be greatly appreciated. [img src=\"style_emoticons/[#EMO_DIR#]/smile.gif\" style=\"vertical-align:middle\" emoid=\":smile:\" border=\"0\" alt=\"smile.gif\" /] Thanks in advance,Impius Quote Link to comment Share on other sites More sharing options...
trq Posted June 21, 2006 Share Posted June 21, 2006 If your just learning then maybe this would be a good place to start. You will find a users ip in the $_SERVER array. Look it up [a href=\"http://php.net/globals\" target=\"_blank\"]here[/a]. Then you'll need to use an if() conditional. Look them up [a href=\"http://php.net/if\" target=\"_blank\"]here[/a]. Quote Link to comment Share on other sites More sharing options...
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