Syntax help, button position

[rollerboy]

Hi,I have a script that validates if a users password is correct. If the password is correct I want to add a button for the user to continue. The script below displays the button if the user is valid or not. When I move the button code to after the line (echo "Welcome back $Username";) I get a parse error. I have also tried to echo out the button like the first 4 lines below but this doesnt work either. Any ideas?? Also what is the simplest way to set a cookie?

echo "<form action= "login_display.php" method="post">";
echo "<input type="submit" value="Continue">";
echo "<input type=\"hidden\" name =\"Username\" value=$Username>";
echo "</form>";

//Password Validate
<?php
include ("customers_inc.php");

$query= "SELECT Password FROM customer_details WHERE Username='$Username'";
$result=mysql_query($query);
$num=mysql_num_rows($result);

if ($num ==0)
{
echo "The database contains no contacts yet";
}
else
{
echo "<b><centre> Contacts</centre></b><br><br>";
?>


<?
$i=0;
while ($i<$num)
{
$db_Password=mysql_result($result, $i, "Password");
?>


<?
$i++;
}
//60
echo "</table>";
}
?>
<?
if (($db_Password)===($Password))
{
echo "Welcome back $Username";
}
else
{
echo "<b><centre> Invalid user</centre></b><br><br>";
echo "Please try again <a href=\"index2.php\"> Insert details</a><br>";
}
?>
<form action= "login_display.php" method="post">
<input type="submit" value="Continue">
<? echo "<input type=\"hidden\" name =\"Username\" value=$Username>"; ?>
</form>


Thanks in advance for any help

[phpstuck]

Try this and see if it works:

[code]

//top part cut off for easy reading

if (($db_Password)===($Password))
{
echo "Welcome back $Username";
echo"<br><br><form action= 'login_display.php' method='post'>
<input type='submit' value='Continue'>
<input type='hidden' name ='Username' value=$Username>
</form>";
?>
}
else
{
echo "<b><centre> Invalid user</centre></b><br><br>";
echo "Please try again <a href=\"index2.php\"> Insert details</a><br>";
}
?>
[/code]