[SOLVED] Need some help (GD library)

[slpctrl]

<?php
function getpixels($pic){
$image = imagecreatefromjpeg($pic);
list($width, $height) = getimagesize($pic);
$height = $height/2;
$vars = array();
for ($i=0; $i<=$width; $i++){
  $color = imagecolorat($image, $i, $height);
  array_push($vars, $color);
  return $vars;
}
}
$pixls = getpixels("world.jpg");
foreach($pixls as $pixl){
echo "$pixl<br />";
}
?>

 

What I was trying to do here was to get the hex color code of each pixel across an image, but the code returns numbers like this: "162486" which clearly isn't any hex color codes. How can I modify this to return the hex color value of each pixel?

[slpctrl]

Never mind, I just put the return vars in the wrong spot. This does it:

 

<?php
function getpixels($pic){
$image = imagecreatefromjpeg($pic);
list($width, $height) = getimagesize($pic);
$height = $height/2;
$vars = array();
for ($i=0; $i<=$width; $i++){
  $color = imagecolorat($image, $i, $height);
  array_push($vars, $color);
}
return $vars;
}
$pixls = getpixels("world.jpg");
foreach($pixls as $pixl){
echo "$pixl<br />";
}
?>

[slpctrl]

Actually, I could use help on one more thing. The 'image' that I'm using here is drawn in php, and is a PHP file. It's MIME type is a .png, but when I enter the .php file as the image obviously it doesn't work. How can I work around this?  ???

[slpctrl]

Fixed that too. The PHP drew the file with the MIME type of PNG, and I was using imagecreatefromjpg. Simply changing jpg to png solved that.