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Perl to PHP


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I need some help, i am trying to convert everything i have into PHP... currently i have it in JSP,Perl,PHP,.... and anything else you might think of, ive run into a small problem with crypt.... i was wondering if any one could help me.

the Perl version:
[code]
#!/usr/bin/perl

if( $#ARGV != 0 )
{
  print "usage: vcrypt password\n";
  exit 1;
}
my $salt = join '', ('.', '/', 0..9,'A'..'Z', 'a'..'z')[rand 64, rand 64];
print crypt($ARGV[0], $salt) ."\n";
[/code]

how would i write the same thing in PHP??
Would i just have to use
[code]crypt($password);[/code]
without a salt? or would i need to continue to specify that specific salt, and how would PHP accept that?

any help would be greatful.
-Branden
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well in perl you can use the "crypt" function and similar to php you can "salt" the string to be crypted
basically telling the function what can be used (character wise) to crypt the password in this case
the ones mentioned previously.
i see that with the crypt function i can

[code]crypt($password , $salt); [/code]

but it doesnt accept the same salt string, like perl does.
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[code]join '', ('.', '/', 0..9,'A'..'Z', 'a'..'z')[rand 64, rand 64];[/code]

., /, the range 0-9, the range A-Z, and the range a-z are within a list () and make up 64 characters. The list is being sliced [] with two random indexes. For example, [0, 1] would give you '.' and '/'.
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This isn't [i]exactly[/i] what it's doing (code for code), but same difference--getting two random values from the array.

[code]<?php

$array = array(
'.',
'/',
);
$array = array_merge(
$array,
range(0, 9),
range('A', 'Z'),
range('a', 'z')
);

shuffle($array);
echo $salt = array_pop($array) . array_shift($array);

?>[/code]
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well i feel kinda stupid...

This doesnt work:
[code]
crypt($password, ./[0-9A-Za-Z][rand 64,rand 64])
[/code]

This does:
[code]
crypt($password, "./[0-9A-Za-Z][rand 64,rand 64]")
[/code]

all i missed were the freakin quotes, guess thats what happens when you spend too much time infront of the computer
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