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[SOLVED] Why won't this work with protype.


Just_Johnny

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I'm using this example here. http://www.php-learn-it.com/tutorials/starting_with_php_and_ajax.html

 

This is where I run into my problem.

<?php include("connect_database.php");
<html>
<head>		
	<script type="text/javascript" src="prototype.js"></script>
	<script>

		function sendRequest() {
			new Ajax.Request("test.php", 
				{ 
				method: 'post', 
				postBody: 'name='+ $F('name'),
				onComplete: showResponse 
				});
			}

		function showResponse(req){
			$('show').innerHTML= req.responseText;
		}
	</script>
</head>

<body>
	<form id="test" onsubmit="return false;">
		<select name="name" id="name" >

                                      //everything goes wrong here

                                       $query = mysql_query("SELECT * FROM cars");
                                       while($rows=mysql_fetch_array($query)){
                                       $make = $rows['make'];
                                      
                                       echo"<option value='".$make."'>".$make."</option>";
                                      
                                      //end everything goes wrong

                                      </select>
		<input type="submit" value="submit" onClick="sendRequest()">
	</form>

	<div id="show"></div>
</body>

</html>

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