jmr3460 Posted May 31, 2009 Share Posted May 31, 2009 I am having some issues with a script that I am working with. I am going to start with the first part of the script and work my way to the end. I don't know if I am actually getting into the db. When I run this file I get this on browser>  This is my code: <? /** * Connect to the mysql database. */ $host = "localhost"; $user = "username"; $password = "password"; $database = "database_name"; $conn = mysql_connect($host, $user, $password) or die("could nit get in" . mysql_error() ); mysql_select_db($database, $conn) or die("could nit get in db" . mysql_error()); ?> Can anyone help me? Thanks for any knowledge. Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/ Share on other sites More sharing options...
Ken2k7 Posted May 31, 2009 Share Posted May 31, 2009 It appears correct. I assume your information is correct as well so try changing <? to <?php. Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/#findComment-846022 Share on other sites More sharing options...
jmr3460 Posted May 31, 2009 Author Share Posted May 31, 2009 I changed the <? to <?php and the i>>with the upside down ? disapeared. thanks So you think I got in? How can I verify this I get a white screen when I render this code. Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/#findComment-846025 Share on other sites More sharing options...
Ken2k7 Posted May 31, 2009 Share Posted May 31, 2009 Just run some SQL - <?php /** * Connect to the mysql database. */ $host = "localhost"; $user = "username"; $password = "password"; $database = "database_name"; $conn = mysql_connect($host, $user, $password) or die("could nit get in" . mysql_error() ); mysql_select_db($database, $conn) or die("could nit get in db" . mysql_error()); $sql = 'SHOW TABLES;'; $results = mysql_query($sql) or die('sql failed - ' . mysql_error()); while ($row = mysql_fetch_assoc($results)) var_dump($row); If you see something other than errors, then it works. Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/#findComment-846028 Share on other sites More sharing options...
jmr3460 Posted May 31, 2009 Author Share Posted May 31, 2009 I tried this: <?php /** * Connect to the mysql database. */ $host = "localhost"; $user = "simplic5_jmr3460"; $password = "freedom98714"; $database = "simplic5_users"; $conn = mysql_connect($host, $user, $password) or die("could not get in" . mysql_error() ); mysql_select_db($database, $conn) or die("could not get in db" . mysql_error()); $q = "select username from users where username = '$username'"; $result = mysql_query($q,$conn); echo "$result"; ?> I got this on my browser: Resource id #2 Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/#findComment-846031 Share on other sites More sharing options...
jmr3460 Posted May 31, 2009 Author Share Posted May 31, 2009 OK I tried what you requested and I got this: array(1) { ["Tables_in_simplic5_users"]=> string(10) "auth_users" } array(1) { ["Tables_in_simplic5_users"]=> string(5) "users" } Looks like I am getting in. I have two tables users and auth_users. Thanks for all of your help. Link to comment https://forums.phpfreaks.com/topic/160321-solved-did-i-get-in-or-not/#findComment-846033 Share on other sites More sharing options...
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