Woodburn2006 Posted August 5, 2006 Share Posted August 5, 2006 i am getting results from a database and i want there to be 3 results on each row, so that when 3 results have been displayed it creates a new line and displays the next 3 results there. i have tried but cannot seem to do it. this is the code that i tried with:[code]<table width='150' border='0' cellspacing='2' cellpadding='0'><tr> <?$cell_count = 0;while ($row = mysql_fetch_array($result)) { if ($cell_count % 2){ extract($row); $price = "£$price"; echo "</tr><tr>"; $cell_count++;}else{echo " <td><div align='center'><img name='' src='' width='150' height='150' alt='' style='background-color: #CCCCCC'></td>";$cell_count++;}}?> </tr></table>[/code]anyone know how i can solve this? Quote Link to comment Share on other sites More sharing options...
redarrow Posted August 5, 2006 Share Posted August 5, 2006 http://www.php-mysql-tutorial.com/php-mysql-paging.phpuse this linl an see the example how to inplement the pagginton Quote Link to comment Share on other sites More sharing options...
Woodburn2006 Posted August 5, 2006 Author Share Posted August 5, 2006 ok thanks, but i fail to see how i can use it.i want 3 images on each row.thanks Quote Link to comment Share on other sites More sharing options...
ronverdonk Posted August 5, 2006 Share Posted August 5, 2006 We have had this topic twice over the last 2 days. See threads [url=http://www.phpfreaks.com/forums/index.php/topic,102715.0.html]http://www.phpfreaks.com/forums/index.php/topic,102715.0.html[/url] and [url=http://www.phpfreaks.com/forums/index.php/topic,103051.0.html]http://www.phpfreaks.com/forums/index.php/topic,103051.0.html[/url] Quote Link to comment Share on other sites More sharing options...
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