anthonydamasco Posted August 7, 2006 Share Posted August 7, 2006 I'm basicly trying to get this script to workMy MySQL table is called 'joborder' and the field is 'checkedby' by default 'checkedby' is set to post "no one" Basicly I want an if then statment to do thisIf 'checkedby' == value "No one" Then echo ' 'Else include "checkid.html"but I dont know the correct way to do it.[code=php:0] <?php$checkedby = $my_row['checkedby']; if($checkedby == 'no one'){ echo '';}else{ include_once("checkid.html");} ?>[/code]but i know im doing something wrong. Quote Link to comment Share on other sites More sharing options...
Orio Posted August 7, 2006 Share Posted August 7, 2006 Try:[code]<?php$checkedby = $my_row['checkedby'];if(strtolower($checkedby) != "no one"){include_once("checkid.html");} ?>[/code]Orio. Quote Link to comment Share on other sites More sharing options...
radalin Posted August 7, 2006 Share Posted August 7, 2006 Well try using "No one" instead of "no one". PHP is a case sensitive language just like dbs.Maybe there is a problem with your default post at "no one" try echoing the data you fetch first. See what it's even a space character can break that if statement. "no one" != "no one".Above that logic looks ok Quote Link to comment Share on other sites More sharing options...
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