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date


brown2005

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[code]
<?php
function parsedate($date){
  $str = strtotime($date);
  $today = date('Y-m-d');
  $todaystr = strtotime($today);
  $diff = $todaystr-$str;
  $newdate = date('l jS \of F Y',time()- $diff);
  return $newdate;
}
?>
[/code]

Im not sure if it is necessary to use this:
  $today = date('Y-m-d');
  $todaystr = strtotime($today);

Perhaps i could have simpy used the time() function, but i wasn't sure if i may run into problems given that the format of the date being passed to the function is the Y-m-d and as such will not include the time for any hours during that day.
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