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php image creation in another page.


Crazydog115

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Is it something like this that you want?

[url=http://www.dizzie.co.uk/php/test.php]http://www.dizzie.co.uk/php/test.php[/url]

This page (test.php) check's to see if a form value (in this instance 'name') is set.  If it's set then it calls image.php and displays the result on test.php, if not it displays the form on test.php.

Here's the code for the two pages, with correct content header types.

test.php
[code]
<?php
header("Content-Type: text/html");
if (!isset($_POST['name'])){
?>
<h4>Enter your firstname</h4>
<form action="test.php" method="post">
<input type="text" name="name">
<input type="submit" name="submit" value="Create Image">
<?php
}
else {
?>
<img src="image.php?name=<?php echo $_POST['name'] ?>">
<br><br><a href="test.php">Try again</a>
<?php
}
?>
[/code]

Here's the code for image.php

[code]
<?php
  header("Content-type: image/png");
  $string = $_GET['name'];
  $im = imagecreatefrompng("../logos/pubutton.png");
  $height = imagesy($im);
  $halfheight = $height / 2;
  $width = imagesx($im);
  $halfwidth = $width / 2;
  $fontsize = 48;
  $angle = 0;
  $font = "../logos/smartie.ttf";
  $bg = imagecolorallocate($im, 255,255,255);
  $white = imagecolorallocate($im,255,255,255);
  $black = imagecolorallocate($im,0,0,0);
  $array  = imagettfbbox($fontsize,$angle,$font,$string);
  $textwidth = abs($array[2] - $array[0]);
  $halftextwidth = $textwidth / 2;
  $textheight = abs($array[5] - $array[3]);
  $halftextheight = $textheight / 2;
  $xpos = $halfwidth - $halftextwidth;
  $ypos = $halfheight + $halftextheight;
  imagettftext($im, $fontsize, $angle, $xpos, $ypos, $black, $font, $string);
  imagepng($im);
  imagedestroy($im);
?>
[/code]

Obviously your image.php file would probably look a lot different from mine.

Regards
Rich
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