Buglish Posted August 23, 2006 Share Posted August 23, 2006 Hi I am a newbie at PHP and MySQL.I have this function that is suppose to insert the values into the temp database.I am sure the values are being passed and splited from file(CSV) into the correct variables.But when it must write to database the Data is not writen.Is there something wrong with my syntax?I do get the Last echo, that means all fields has been processed...but still no data in DB.//------------------------------------------------------------------<?php function breakname($fullnamein) { $fullnamebreak = explode(" ",$fullnamein); //inticate that these variables are the gobal ones not local ones global $title,$initials,$surname; for($p=0;$p<3;$p++) { switch($p) { case 0 :$title = $fullnamebreak[$p];break; case 1 :$initials = $fullnamebreak[$p];break; case 2 :$surname = $fullnamebreak[$p];break; } } }//$link = "/EclipseWorkspace/LPCL101/files/*.php";//Test File /EclipseWorkspace/LPCL101/files/eov321_2006.csv//add the refix http to the link to use abolute access$link = "http://localhost/".$link; $parts = explode(" ",$format); //break the input format into parts$db = mysql_connect("localhost","root","password1");//connect to database//open file or catch error$file = fopen($link, "r") or exit("Unable to open file!<br><br>" . "<a href='extract_data_file.php'>Back</a>");//create a temp password for student = 12345$password = 12345;$x=1; //Type holder//Read a line of the file until the end is reached while(!feof($file)){ $line= fgets($file);//read line $linebreak = explode(",",$line );//break up the line for($i=0;$i<3;$i++) { switch($parts[$i]) { case "%name" : breakname($linebreak[$i]); break; case "%num" : $lnumber = $linebreak[$i]; break; case "%course": $course = $linebreak[$i]; break; } } //Write line data to database mysql_select_db("Students",$db); $sql = "INSERT INTO Students (S_StudentNum,S_Password,S_Surname,S_Title,S_Initials) VALUES ('$lnumber','$password','$surname','$title','$initials')"; $result = mysql_query($sql); //Write line data into Course links mysql_select_db("CourseLinks",$db); $sql = "INSERT INTO CourseLinks (CL_Type,CL_Person,CL_Course) VALUES ('$x','$lnumber','$course')"; $result = mysql_query($sql); }fclose($file);echo "Thank you! Information updated.<br>"; ?> Quote Link to comment Share on other sites More sharing options...
448191 Posted August 23, 2006 Share Posted August 23, 2006 You don't check for errors returned after executing queries. [code]<?php$result = mysql_query($sql) or die('Query: "'.$sql.'" failed, MySQL returned: "'.mysql_error().'"');?>[/code]It IS [url=http://www.phpfreaks.com/forums/index.php/topic,95443.0.html]in the FAQ[/url] you know... Quote Link to comment Share on other sites More sharing options...
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