INSERT help for Newbie

kirkenall · January 11, 2010

Hi good people. I am trying to put together a simple application where I take info from an html form and insert it into a mySQL db. everything appears to work proper but a new record is never actually created in the db. Below is the PHP code. Thanks in advance for any assistance.

<?php

$con = mysql_connect ("localhost", "root", "xxxx");

if (!$con)

{

die('Could not connect: ' . mysql_error());

}

mysql_select_db ("registrants")or die(mysql_error());

$ebits = ini_get('error_reporting');

error_reporting($ebits ^ E_NOTICE);

$firstname =$_POST["firstname"];

$lastname = $_POST["lastname"];

$dateofbirth =$_POST["dateofbirth"];

$ss = $_POST["ss"];

$address = $_POST["address"];

$apt = $_POST["apt"];

$city = $_POST["city"];

$state =$_POST["state"];

$zip = $_POST["zip"];

$email = $_POST["email"];

$homephone = $_POST["homephone"];

$cell = $_POST["cell"];

$Sex = $_POST["Sex"];

$maritalstat = $_POST["maritalstat"];

$race = $_POST["race"];

$citizen = $_POST["citizen"];

mysql_query ("INSERT INTO registrants (first name, last name, date of birth, ss#, address, city, state, zipcode, email, homephone, cellphone, sex, marriage, ethnicity, citizen, apt#, id) Values ('$firstname', '$lastname', '$dateofbirth', '$ss', '$address', '$city', '$state', '$zip', '$email', '$homephone', '$cell', '$Sex', '$maritalstat', '$race', '$citizen', '$apt', 'NULL')");

?>

kirkenall · January 11, 2010

Here is the form info:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<head>

<title>Registration</title>

<!--

body {

background-color: #F90;

font-size: medium;

}

#form1 table tr td div label {

color: #FFF;

}

#form1 table {

color: #FFF;

font-size: 24px;

}

-->

</style></head>

<body>

</label>

<tr>

<div align="right">First Name</div>

</label> </td>

</div></td>

</tr>

<tr>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Date of Birth</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Social Security #</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Address</div>

</label> </td>

</div></td>

</tr>

<tr>

</label> </td>

</div></td>

</tr>

<tr>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">State</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Zipcode</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">email Address</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Home Phone</div>

</label> </td>

</div></td>

</tr>

<tr>

<div align="right">Cell Phone</div>

</label> </td>

</div></td>

</tr>

<tr>

</label> </td>

<p>

<label>

Male</label>

<label>

Female</label>

<br />

</p>

</div></td>

</tr>

<tr>

<div align="right">Marital Status</div>

</label> </td>

<option value="1">Never Married</option>

<option value="2">Divorced</option>

<option value="3">Widowed</option>

<option value="4">Separated</option>

<option value="5">Married</option>

</select></td>

</tr>

<tr>

<label for="race">Race/Ethnicity</label>

</div></td>

<option value="1">African American</option>

<option value="2">Hispanic or Latino</option>

<option value="3">American Indian or Native Alaskan</option>

<option value="4">White or Caucasian</option>

<option value="5">Multi-racial</option>

<option value="6">Asian Pacific Islander</option>

<option value="7">Other</option>

</select></td>

</tr>

<tr>

<p><label>Are you a US Citizen?</label><br />

</p>

</div></td>

<label>Yes

No </label></td>

</tr>

<tr>

</tr>

<tr>

</div></td>

</tr>

</table>

</form>

</body>

</html>

Catfish · January 11, 2010

check your mysql query works with an if() conditional and output the error on failure:

if (mysql_query ("INSERT INTO registrants (first name, last name, date of birth, ss#, address, city, state, zipcode, email, homephone, cellphone, sex, marriage, ethnicity, citizen, apt#, id) Values ('$firstname', '$lastname', '$dateofbirth', '$ss', '$address', '$city', '$state', '$zip', '$email', '$homephone', '$cell', '$Sex', '$maritalstat', '$race', '$citizen', '$apt', 'NULL')"))
{
   // succeeded. continue with code
}
else
   print("Could not INSERT data to database. Error given: ".mysql_error()."<br/>\n");

the link in my signature has a short topic on flow control which shows you this method to validate all your script's actions as you go. it's a handy way to code.

Adam · January 11, 2010

Here's your problem:

mysql_query ("INSERT INTO registrants (first name, last name, date of birth, ss#, address, city, state, zipcode, email, homephone, cellphone, sex, marriage, ethnicity, citizen, apt#, id) Values ('$firstname', '$lastname', '$dateofbirth', '$ss', '$address', '$city', '$state', '$zip', '$email', '$homephone', '$cell', '$Sex', '$maritalstat', '$race', '$citizen', '$apt', 'NULL')");

kirkenall · January 11, 2010

Catfish---thanks for the reply,

I tried your code and received the following error: Could not INSERT data to database. Error given: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'name, last name, date of birth, ss#, address, city, state, zipcode, email, homep' at line 1

kirkenall · January 11, 2010

MrAdam---thank you too for the reply....I tried your code too and still the same results .....no record is created in the db.

MatthewJ · January 11, 2010

field names with spaces must be enclosed with backticks (`)

kirkenall · January 11, 2010

MattewJ....I am not seeing the field names with spaces......I do not want spaces

MatthewJ · January 11, 2010

"INSERT INTO registrants (first name, last name, date of birth, ss#, address, city, state, zipcode, email, homephone, cellphone, sex, marriage, ethnicity, citizen, apt#, id) Values ('$firstname', '$lastname', '$dateofbirth', '$ss', '$address', '$city', '$state', '$zip', '$email', '$homephone', '$cell', '$Sex', '$maritalstat', '$race', '$citizen', '$apt', 'NULL')"

kirkenall · January 11, 2010

MatthewJ....Same thing. After I changed the code to your rec. I still receive the following after running the code and then checking for a new record in PHPMyAdmin...............................MySQL returned an empty result set (i.e. zero rows).

Lamez · January 11, 2010

in your database, edit the column with the # sign, remove it, then edit your query.

kirkenall · January 11, 2010

I edited out the # sign and am still getting the same result. No record is added to the db when the script is ran.

kirkenall · January 11, 2010

Thanks for all of the help.....you people are great. The problem had to do with having spaces in the column names.

Catfish · January 12, 2010

rofl. that's what he said 6 posts back

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