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str_replace problem


master82

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In my table i have the field 'field1' and an example of its data is below:
[code]
((F*0.8)/1)+(L/4)
[/code]

Its simply a small calculation, which uses the following code:
[code]
$calc="\$rate=".str_replace(array("L","E","F","I"), array($l, $e, $f, $I),$field1).";";
eval($calc);
[/code]

When the code is run I get the following error:
[quote]
Parse error: parse error, unexpected ';' in LOCATION\PAGE.php(60) : eval()'d code on line 1
[/quote]

Any idea what it is i'm doing wrong?

Also Im using $rate later on in the page - will there be a problem with this?
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Use
[code=php:0]$calc = "\$rate = str_replace(array(\"L\",\"E\",\"F\",\"I\"), array(\$l, \$e, \$f, \$I), \$field1);";[/code]

If you are using eval.

However i see no use for eval here. Just use:
[code=php:0]$rate = str_replace(array("L","E","F","I"), array($l, $e, $f, $I), $field1);[/code]
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[quote author=wildteen88 link=topic=106833.msg427692#msg427692 date=1157372216]
Use
[code=php:0]$calc = "\$rate = str_replace(array(\"L\",\"E\",\"F\",\"I\"), array(\$l, \$e, \$f, \$I), \$field1);";[/code]

If you are using eval.

However i see no use for eval here. Just use:
[code=php:0]$rate = str_replace(array("L","E","F","I"), array($l, $e, $f, $I), $field1);[/code]
[/quote]it appears that $field1 contains an equation, the OP is trying to replace Keywords with values, and then execute the equation. eval() will be needed if the OP wants that equation to execute in PHP :)
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