How do include a class inside of a class

[Dat]

How do i use a class inside of another class?

 

I have class blogPost and class database.

 

How do i use database inside class blogPost

 

class blogPost

{

include ('database');

$db = new database;

}

[trq]

class blogPost
{
  private $_db;
  public function __construct($db)
  {
    $this->_db = $db;
  }
}

include ('database');
$blog = new blogPost(new database);

[Dat]

class blogPost
{
  private $_db;
  public function __construct($db)
  {
    $this->_db = $db;
  }
}

include ('database');
$blog = new blogPost(new database);

What if i already have a __construct?

[Axeia]

Then pass the parameter to do that to the construct or create a method

  public function setDatabase($db)
  {
    $this->_db = $db;
  }

 

Although if $this->_db is vital for the blogPost class (which I suspect it is) it belongs in the construct.

 

 

As a few hopefully constructive tips..

 

tip #1

PHP(5) supports type hinting so this works as well:

__construct(database $db)

The more strict you can get the better imo. (Als provides more useful errors when you pass in a parameter of the wrong type)

 

tip #2

You may want to stick to the general PHP (and java and probably other programming languages as well) code convention to start classnames with a capital letter, so Database and BlogPost instead of database/blogPost.

 

(this is gonna be a rather late reply.. left this open in a tab for half a day)

[trq]

What if i already have a __construct?

 

Define another argument to it.

[jcbones]

include ('database');
class blogPost
{
  function __construc() {
$this->db = new database();
}
}

[trq]

include ('database');
class blogPost
{
  function __construc() {
$this->db = new database();
}
}

 

That's not such a good idea, because now the blogPost object is tied to a specific database object.