Using netbeans 6.91 and Zend_gdata_youtube class

[kc111]

Hi ,

 

I'm a new programmer . I hope this is the right place for this:

 

I want to access youtube videos via the Zend_gdata_youtube class. I am developing using wampserver 2.01 and netbeans 6.91.

 

 

  <?php             $yt = new Zend_Gdata_YouTube();      $query = $yt->newVideoQuery();      $query->category = 'Comedy/dog';      echo $query->queryUrl . "\n";      $videoFeed = $yt->getVideoFeed($query);        ?>

 

 

 

I was getting the following error:

 

Warning:

 

require(gdata/youtube.php) [function.require]: failed to open stream: No such file or directory in C:\wamp\www\PhpProject1\index.php on line 10

 

Fatal error: require() [function.require]: Failed opening required 'gdata/youtube.php' (include_path='.;C:\wamp\bin\php\includes;C:\wamp\www\ZendGdata-1.10.8\library') in C:\wamp\www\PhpProject1\index.php on line 10

 

after changing the php.ini file include line to

 

; Windows: "\path1;\path2"

include_path = ".;C:\wamp\bin\php\includes;C:\wamp\www\ZendGdata-1.10.8\library

 

( I got this from http://framework.zend.com/manual/en/learning.quickstart.intro.html )

 

I am getting the following error now:

 

Fatal error: Class 'Zend_Gdata_YouTube' not found in C:\wamp\www\PhpProject1\index.php on line 11

 

Does this make any sense to anyone? I think this just boils down to getting the right include path, but its not clear to me how to figure this out

 

Thanks in advance,

 

KC

[thehippy]

Given:

require(gdata/youtube.php) [function.require]: failed to open stream: No such file or directory in C:\wamp\www\PhpProject1\index.php on line 10

and

include_path = ".;C:\wamp\bin\php\includes;C:\wamp\www\ZendGdata-1.10.8\library

 

If you put those paths together, does that file exist there?

 

Do you see why this isn't working?

[kc111]

Thank you! That worked. - KC