OldWest Posted November 14, 2010 Share Posted November 14, 2010 I've been hacking at this for 3 hours now.. My syntax seems to be screwed up on something, but I cannot find it for the life of me! Error thrown is obvious I am missing or have something nested wrong! Parse error: parse error in C:\wamp\www\php\php_study\login_processor.php on line 22 Here is my code. Error is being thrown on the line of the elseif statment. <?php include('db_cxn.php'); $cxn = mysqli_connect($host, $user, $pass, $db) or die("Query died: connect"); $sql = "SELECT username FROM users WHERE username = '$_POST[username]'"; $result = mysqli_query($cxn, $sql) or die("Query Died: username"); $num = mysqli_num_rows($result); if ($num > 0) { $sql = "SELECT username FROM users WHERE username='$_POST[username]' AND password=md5('$_POST[password]')"; $result2 = mysqli_query($cxn, $sql) or die("Query died: password"); $num2 = mysqli_num_rows($result2); if ($num2 > 0) { $_SESSION['auth']; $_SESSION['logname'] = $_SESSION['username']; } //if ($num2 > 0) header("Location: the_secret_page.php"); } //if ($num > 0) else { $message1 = "The login name, '$_POST[username]' does not exist in the database. Please try again"; $username = strip_tags(trim($_POST[username])); include('login_form.php'); } //else elseif ($num == 0) { $message1 = "The username you entered does not exist. Please try again.s"; include("login_form.php"); } //elseif ($num == 0) ?> I don't think my form html/php code is necessary, but I'll include it for reference: <h1>Login Form</h1> <?php $fields_1 = array("username" => "User Name", "password" => "Password"); ?> <form method="post" action="login_processor.php"> <fieldset> <legend>Login Form</legend> <?php if (isset($message_1)) { echo "$message_1"; } //if (isset($message_1)) foreach ($fields_1 as $field => $value) { if (preg_match("/pass/i", $field)) $type = "password"; else $type = "text"; echo "<div id='field'> <label for='$field'>$value</label> <input id='$field' name='$field' type='$type' value='" . @$$field . "' size='20' maxlength='50' /> </div>\n"; } //foreach ($fields_1 as $field => $value) ?> <input type="submit" name="Button" value="Login" /> </fieldset> </form> Quote Link to comment Share on other sites More sharing options...
OldWest Posted November 14, 2010 Author Share Posted November 14, 2010 I think I just figured it out. My elseif needed to go before the else.. The error is no longer being throw, so my guess is I got it.. My code is far from done (cleaned up and secured), but I'm open for any suggestions or critique on what I have so far.. Quote Link to comment Share on other sites More sharing options...
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