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PHP error, I need help Pls.


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#1 u0206787@nus.edu.sg

u0206787@nus.edu.sg
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Posted 26 September 2006 - 11:34 PM

1. Undefined variable: on line 41 (if ( $signin != "" ) { )
2. Undefined variable: on line 75 (mysql_close($link); { )
3. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 75
4. Undefined variable: on line 77 (if ( $adminsignin != "" ) { )
5. Undefined variable: on line 105 (mysql_close($link); { )
6. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 105

I'm running on EasyPHP 1.8.0.1; with Apache 1.3.33; PHP 4.3.10; MySQL 4.1.9. Pls I need your kind advise. Sorry I can post the code here, keep prompting me error. Hence i have the code in PDF format, pls help me.


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#2 trq

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Posted 26 September 2006 - 11:37 PM

Do not multipost! See your other thread here.




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