Jump to content

Archived

This topic is now archived and is closed to further replies.

u0206787@nus.edu.sg

PHP error, I need help Pls.

Recommended Posts

1. Undefined variable: on line 41 (if ( $signin != "" ) { )
2. Undefined variable: on line 75 (mysql_close($link); { )
3. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 75
4. Undefined variable: on line 77 (if ( $adminsignin != "" ) { )
5. Undefined variable: on line 105 (mysql_close($link); { )
6. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 105

I'm running on EasyPHP 1.8.0.1; with Apache 1.3.33; PHP 4.3.10; MySQL 4.1.9. Pls I need your kind advise. Sorry I can post the code here, keep prompting me error. Hence i have the code in PDF format, pls help me.


[attachment deleted by admin]

Share this post


Link to post
Share on other sites
Do not multipost! See your other thread [url=http://www.phpfreaks.com/forums/index.php/topic,109557.msg441740.html#msg441740]here[/url].

Share this post


Link to post
Share on other sites
Guest
This topic is now closed to further replies.

×

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.