u0206787@nus.edu.sg Posted September 26, 2006 Share Posted September 26, 2006 1. Undefined variable: on line 41 (if ( $signin != "" ) { )2. Undefined variable: on line 75 (mysql_close($link); { )3. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 754. Undefined variable: on line 77 (if ( $adminsignin != "" ) { )5. Undefined variable: on line 105 (mysql_close($link); { )6. mysql_close(): supplied argument is not a valid MySQL-Link resource on line 105I'm running on EasyPHP 1.8.0.1; with Apache 1.3.33; PHP 4.3.10; MySQL 4.1.9. Pls I need your kind advise. Sorry I can post the code here, keep prompting me error. Hence i have the code in PDF format, pls help me. [attachment deleted by admin] Link to comment Share on other sites More sharing options...
trq Posted September 26, 2006 Share Posted September 26, 2006 Do not multipost! See your other thread [url=http://www.phpfreaks.com/forums/index.php/topic,109557.msg441740.html#msg441740]here[/url]. Link to comment Share on other sites More sharing options...
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