printf and display of image

[stressedsue]

Hello,

I want to display an image dynamically within the printf() function, where the image name resides on a database.  How do I embed the image name within the <img src> tag, which is within the printf() function?

Example of code that does not work:

printf("<tr>
    <td>
    <p><img src='../art/'>%s</p>
    </td>
    </tr>\n", $myrow["photoname"]");

Any help is greatly appreciated!!!
 

[Gaoshan]

It is the last " causing you trouble (the one right before the closing parenthesis). Lose it and you should be ok.
Just curious but why use print_r for this? I think a faster solution would be something like:
[code]echo '<tr><td><p><img src="../art/' . $myrow[photoname] . '"></p></td></tr>';[/code]