Jump to content

Newbie In Need of Assistance


aal9_programmer
 Share

Recommended Posts

Hey all, I'm currently working on a website/database system. What i'm trying to achieve atm is for a user to be able to edit current data in a database table, submit it, and for it to display the new data in the webpage. The table i'm reading from has 6 records and the fields ID(which is just auto_incremented) and courseName.

 

Ideally, I would like the user to be able to delete a record too. The code I have written displays the courseName's in a table along with textareas and a submit button for each row. It seems to be doing nothing at the minute, so I was hoping someone could enlighten me as to what I've done wrong and if someone could provide what code i'm missing if any, i would be ever so grateful  :) I think I might have structured it all wrong, I hope this isn't the case! My current code is below, hope to hear some feedback soon, many thanks, Aaron

 

PS: feel free to ask any more question in case I've forgot to mention something

 

<?php
session_start();
$hostname_logon = "***.*.*.*" ;   
$database_logon = "aal9" ;  
$username_logon = "root" ;  
$password_logon = "" ;

$coursenametext = '';
$id = '';
//error_reporting (E_ALL ^ E_NOTICE);

$connections = mysql_connect($hostname_logon, $username_logon, $password_logon) or die ( "Unable to connect to the database" );
mysql_select_db($database_logon) or die ( "Unable to select database!" );
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit Courses</title>
<link href="Aaron.css" rel="stylesheet" type="text/css" />
</head>
<div class="container">
<h1><img src="logo.gif" alt="Logo" width="224" height="62" id="logo" align="left"/></a>Update Courses</h1>
</div>
<div class="sidebar1">
    <ul class="nav">
      <li><a href="homepage.php">Homepage</a></li>
      <li><a href="modules.php">My Modules</a></li>
      <li><a href="update.php">Update Database</a></li>
      <li><a href="googles1.php">Sem 1 Google</a></li>
      <li><a href="timetable2.php">Sem 2 Timetable</a></li>
      <li><a href="googles2.php">Sem 2 Google</a></li>
      <li><a href="logout.php">Logout</a></li>
    </ul>
    <p><a href="javascript:window.print()">Print This Page</a></p>
    <p> Lorem ipsum dolor sit amet, consectetur adipiscing elit. Integer nec odio. Praesent libero. Sed cursus ante dapibus diam. Sed nisi. Nulla quis sem at nibh elementum imperdiet. Duis sagittis ipsum. Praesent mauris. Fusce nec tellus sed augue semper porta. Mauris massa. Vestibulum lacinia arcu eget nulla. </p>
    <p>Welcome To Timetable Management. Please Find All Necessary Links Above.</p>
</div>
<div class="content">
<form action="editcourses.php" method="post">
<table border="1" cellspacing="1" align="center" bordercolor="#FFFFFF">
<tr>
<td>Course Name</td>
<td>Edit</td>
<td>Submit</td>
<td>Delete</td>
</tr>
<?php
$query = "SELECT * FROM Courses ";
$result = mysql_query ($query);
if(mysql_num_rows($result)>0){
                while($row = mysql_fetch_array($result)) {
                echo('<tr>' .
                '<td>' . $row['CourseName'] . '</td>' .
                '<td><input type="hidden" name="id" value="' . $row['ID'] . '"/><textarea name="coursenametext" rows="2"></textarea>' . '</td>' .
                '<td>' . '<input type="Submit" name="Submit" value="Submit">' . '</td>' .
                '</tr>');
        }
}
if(isset($_POST['Submit']))
{
$query1 = "UPDATE courses SET courseName = '".$_POST['coursenametext']."' WHERE ID = '".$_POST['id']."'";
$result1 = mysql_query ($query1);
}
?>
</table>    
</form>
<br>
</div>
<div class="footer">
<p><a href="mailto:***@**.**.**" class="Email">Click Here To Email For Help With Faults</a></p>
</div>
</div>
</body>
</html>

Link to comment
Share on other sites

You are putting your textarea 'coursenametext' into a loop. therefore if you have 6 textareas they are all going to have the same name, so the form will more than likely only take the value from the last textarea ( number 6) and ignore the rest, regardless of which submit button you are pressing

Link to comment
Share on other sites

Hi, the hole you have fallen into is that you are dynamically genterating multiple Id's and textareas in a single form. So when you post the data you are posting 6 textareas and 6 seperate ids. The form will automatically grab the last id and textarea. so it will always submit ID6 and textarea 6.

 

What you want to do in essence is to dynamically create 6 DIFFERENT FORMS. So all you need to do is move your form tags into the while loops. So, from this:

<form action="editcourses.php" method="post">
<table border="1" cellspacing="1" align="center" bordercolor="#FFFFFF">
<tr>
<td>Course Name</td>
<td>Edit</td>
<td>Submit</td>
<td>Delete</td>
</tr>
<?php
$query = "SELECT * FROM Courses ";
$result = mysql_query ($query);
if(mysql_num_rows($result)>0){
                while($row = mysql_fetch_array($result)) {
                echo('<tr>' .
                '<td>' . $row['CourseName'] . '</td>' .
                '<td><input type="hidden" name="id" value="' . $row['ID'] . '"/><textarea name="coursenametext" rows="2"></textarea>' . '</td>' .
                '<td>' . '<input type="Submit" name="Submit" value="Submit">' . '</td>' .
                '</tr>');
        }
}
if(isset($_POST['Submit']))
{
$query1 = "UPDATE courses SET courseName = '".$_POST['coursenametext']."' WHERE ID = '".$_POST['id']."'";
$result1 = mysql_query ($query1);
}
?>
</table>    
</form>

 

to this:


<table border="1" cellspacing="1" align="center" bordercolor="#FFFFFF">
<tr>
<td>Course Name</td>
<td>Edit</td>
<td>Submit</td>
<td>Delete</td>
</tr>
<?php
$query = "SELECT * FROM Courses ";
$result = mysql_query ($query);
if(mysql_num_rows($result)>0){
                while($row = mysql_fetch_array($result)) {
                echo'<form action="editcourses.php" method="post">';
                echo('<tr>' .
                '<td>' . $row['CourseName'] . '</td>' .
                '<td><input type="hidden" name="id" value="' . $row['ID'] . '"/><textarea name="coursenametext" rows="2"></textarea>' . '</td>' .
                '<td>' . '<input type="Submit" name="Submit" value="Submit">' . '</td>' .
                '</tr>'
                '</form>';
);
        }
}
if(isset($_POST['Submit']))
{
$query1 = "UPDATE courses SET courseName = '".$_POST['coursenametext']."' WHERE ID = '".$_POST['id']."'";
$result1 = mysql_query ($query1);
}
?>
</table>    

 

Link to comment
Share on other sites

 

try:

<table border="1" cellspacing="1" align="center" bordercolor="#FFFFFF">
<tr>
<td>Course Name</td>
<td>Edit</td>
<td>Submit</td>
<td>Delete</td>
</tr>
<?php
$query = "SELECT * FROM Courses ";
$result = mysql_query ($query);
if(mysql_num_rows($result)>0){
                while($row = mysql_fetch_array($result)) {
                echo'<form action="editcourses.php" method="post">';
                echo('<tr>' .
                '<td>' . $row['CourseName'] . '</td>' .
                '<td><input type="hidden" name="id" value="' . $row['ID'] . '"/><textarea name="coursenametext" rows="2"></textarea>' . '</td>' .
                '<td>' . '<input type="Submit" name="Submit" value="Submit">' . '</td>' .
                '<td>' . '<input type="Submit" name="Delete" value="Delete">' . '</td>' .
                '</tr>'
                '</form>';
);
        }
}
if(isset($_POST['Submit']))
{
$query1 = "UPDATE courses SET courseName = '".$_POST['coursenametext']."' WHERE ID = '".$_POST['id']."'";
$result1 = mysql_query ($query1);
}
if(isset($_POST['Delete']))
{
$query1 = "Delete FROM  courses WHERE ID = '".$_POST['id']."'";
$result1 = mysql_query ($query1);
}
?>
</table>    

 

and as for adding a new one, you just need to create a new form outside of the loop and name the button create etc......

Link to comment
Share on other sites

This thread is more than a year old.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

 Share

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.