Meza44 Posted October 6, 2006 Share Posted October 6, 2006 I get this error message from my code and I don't know why. I am new to php.Warning: mysql_numrows(): supplied argument is not a valid MySQL result resource in /home/content/i/b/e/ibezamn/html/change.php on line 15<html><head><title>Ibezamn - Update</title></head><?$id=$_GET['id'];include("capsroster.inc.php");mysql_connect(localhost,$username,$password);$query="SELECT * FROM roster WHERE id='$id'";$result=mysql_query($query);$num=mysql_numrows($result);mysql_close();$i=0;while($i<$num) {$first=mysql_result($result,$i,"first");$last=mysql_result($result,$i,"last");$number=mysql_result($result,$i,"number");$position=mysql_result($result,$i,"position");$height=mysql_result($result,$i,"height");$weight=mysql_result($result,$i,"weight");$shoots=mysql_result($result,$i,"shoots");$dob=mysql_result($result,$i,"dob");?><form action="update.php" method="get"><input type="hidden" name="ud_id" value="<? echo $id; ?>"><br>First:<input type="text" name="ud_first" value="<? echo $first; ?>"><br>Last:<input type="hidden" name="ud_last" value="<? echo $last; ?>"><br>Number:<input type="hidden" name="ud_number" value="<? echo $number; ?>"><br>Height:<input type="hidden" name="ud_height" value="<? echo $height; ?>"><br>Weight:<input type="hidden" name="ud_weight" value="<? echo $weight; ?>"><br>Shoots:<input type="hidden" name="ud_shoots" value="<? echo $shoots; ?>"><br>DOB:<input type="hidden" name="ud_dob" value="<? echo $dob; ?>"><br><input type="submit" value='Update"></form><?++$i;}?></body></html> Quote Link to comment Share on other sites More sharing options...
thedarkwinter Posted October 6, 2006 Share Posted October 6, 2006 Hi, ylou probably justy need to select the databasemysql_connect(localhost,$username,$password);[color=blue]mysql_select_db("mydbname");[/color]$query="SELECT * FROM roster WHERE id='$id'";$result=mysql_query($query);$num=mysql_numrows($result);mysql_close();cheers,tdw Quote Link to comment Share on other sites More sharing options...
steveclondon Posted October 6, 2006 Share Posted October 6, 2006 also add this after you query and see if there are any errors$result=mysql_query($query) or die(mysql_error()); Quote Link to comment Share on other sites More sharing options...
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