Check if in array but not include some values in the array

[Ricky55]

I have an array created to control the down states of the my buttons in my navigation. Which is working well. This array will have quite a few strings in it before I'm done.

 

I then want to conditionally load a CSS file for all the files in that array with the exception of two, is this possible?

 

In plain in english I want to say If in array apart from these values then load my css file.

 

My array (will have more values when complete)

 

$otherTitles = array('Product Selector', 'Avon Range', 'Knightsbridge Range', 'Kingston Range' );

 

My code to load a css file

 

<?php if (in_array($title, $otherTitles)) { ?>
<link rel="stylesheet" type="text/css" href="homepage.css"/>
<?php } ?>

 

I want all titles in the otherTitles array to get this CSS file apart from two Product Selector and Avon Range.

 

Thanks

 

Richard

 

[codebyren]

If I understand what you're asking, you could just use a nested if statement. Something like:

 

<?php if (in_array($title, $otherTitles)): ?>
    <?php if ($title != 'Product Selector' && $title != 'Avon Range'): ?>
	<link rel="stylesheet" type="text/css" href="homepage.css"/>
<?php endif; ?>
<?php endif; ?>

[Ricky55]

That's exactly what I meant thanks very much. Its only a small CSS anyway but not point in loading it if it doesn't need to be loaded.

 

Didn't know you could do nested statements like this (obviously)

 

Thanks very much!