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date post to db


sofia403

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hello i have a question. i have a drop down form to select DD-MM-YEAR , but im unsure how to actually post it into one column DATE since values are given in three separate dropdown options?

 

here is an example of my html, and i would like a php code to be able to post that to mysql. i have it working for other dropdown menus, but not sure how would it work with a date. im very new to php and mysql and any help would be much appreciated. thank you.

 

<select name="Date" id="Date" class="regularfont"><option value="" selected="selected"></option>

<option value="1">01</option>

<option value="2">02</option>

 

</select> <select name="Date" id="Date" class="regularfont"><option value="" selected="selected"></option>

<option value="1">January</option>

<option value="2">February</option>

 

</select> <select name="Date" id="Date" class="regularfont"><option value="" selected="selected"></option>

<option value="2014">2014</option>

<option value="2013">2013</option>

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firstly change you select names to "Day" "Month" "Year" accordingly, then you could simply combine the 3 to form a legitimate date to insert into your db. like so

 

$date = $_POST['day'] . "-" . $_POST['Month'] . "-" . $_POST['Year'];

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thanks for quick response fugix,

 

however im having troubles still, not sure if i have everything entered correctly though.

 

i have a form which is being posted by php to mysql

 

here is my html:

 

<form name="DATE1" method="post">

<div><select name="day" id="Date1" class="regularfont"><option value="" selected="selected"></option>

<option value="1">01</option>

<option value="2">02</option>

</select> <select name="month" id="Date2" class="regularfont"><option value="" selected="selected"></option>

<option value="1">January</option>

<option value="2">February</option>

</select> <select name="year" id="Date3" class="regularfont"><option value="" selected="selected"></option>

<option value="2014">2014</option>

<option value="2013">2013</option>

 

 

on submit it passed on to php

 

<?php

$Date1 = $_POST['day'] . "-" . $_POST['month'] . "-" . $_POST['year'];

?>

 

 

 

what am i doing wrong ?

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thanks for quick response fugix,

 

however im having troubles still, not sure if i have everything entered correctly though.

 

i have a form which is being posted by php to mysql

 

here is my html:

 

<form name="DATE1" method="post">

<div><select name="day" id="Date1" class="regularfont"><option value="" selected="selected"></option>

<option value="1">01</option>

<option value="2">02</option>

</select> <select name="month" id="Date2" class="regularfont"><option value="" selected="selected"></option>

<option value="1">January</option>

<option value="2">February</option>

</select> <select name="year" id="Date3" class="regularfont"><option value="" selected="selected"></option>

<option value="2014">2014</option>

<option value="2013">2013</option>

 

 

on submit it passed on to php

 

<?php

$Date1 = $_POST['day'] . "-" . $_POST['month'] . "-" . $_POST['year'];

?>

 

 

 

what am i doing wrong ?

well, what is happening when the form is sent?

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i have some other forms in  a dropdown menu with different form names

 

those get passed on and entered into mysql by php, but the date one doesnt get updated, just 00-00-0000

 

should i post the whole html and php?

yes if you wouldn't mind, so i can see how you are going about this

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here is my HTML

 

<html>

<head>

<?php

$hostname = "localhost";

$db_user = "";

$db_password = "";

$database = "";

$db_table = "";

$db = mysql_connect($hostname, $db_user, $db_password);

mysql_select_db($database,$db);

?>

<script type="text/javascript" src="js/jquery-1.5.2.min.js"></script>

<script type="text/javascript" src="js/jquery.validate.min.js"></script>

<script type="text/javascript" src="js/additional-methods.min.js"></script>

</head>

<body>

 

 

<form id="signupForm" method="POST" action="processform.php">

<fieldset>

<legend>Signup Form</legend>

<label for="Country">*Country:</label>

<form name="Country" method="post">

<div><select name="Country">

<option value="">-----</option>

<option value="Canada">Canada</option>

<option value="UK">UK</option>

<option value="France">France</option></select></div></p>

 

<p><label for="Nationality">*Nationality:</label>

<form name="Nationality" method="post">

<div><select name="Nationality">

<option value="">-----</option>

<option value="Afghanistan">Afghanistan</option>

<option value="Albania">Albania</option>

<option value="Algeria">Algeria</option></select></div></p>

 

<p><label for="Province">*Province:</label>

<form name="Province" method="post">

<div><select name="Province">

<option value="">-----</option>

<option value="British Columbia">British Columbia</option>

<option value="Alberta">Alberta</option>

<option value="Saskatchewan">Saskatchewan</option></select></div></p>

 

<p><label for="DATE1">*Date:</label>

<form name="DATE1" method="post">

<div><select name="day" id="Date1" class="regularfont"><option value="" selected="selected"></option>

<option value="1">01</option>

<option value="2">02</option>

<option value="3">03</option></select>

 

<select name="month" id="Date2" class="regularfont"><option value="" selected="selected"></option>

<option value="1">January</option>

<option value="2">February</option>

<option value="3">March</option></select>

 

<select name="year" id="Date3" class="regularfont"><option value="" selected="selected"></option>

<option value="2014">2014</option>

<option value="2013">2013</option>

<option value="2012">2012</option></select></div></p></fieldset>

<p>

<div align="center"><input type="submit" name="submit" value="Submit your entry"></div>

</form>

</div></p><?php

}

?>

</body>

</html>

and my PHP processform.php

 

<?php

$hostname = "localhost";

$db_user = "";

$db_password = "";

$database = "";

$db_table = "";

$db = mysql_connect($hostname, $db_user, $db_password);

mysql_select_db($database,$db);

?>

 

<?php

if (isset($_REQUEST['submit'])) {

$sql = "INSERT INTO $db_table(Country,Nationality,Province,DATE1) values ('".mysql_real_escape_string(stripslashes($_REQUEST['Country']))."','".mysql_real_escape_string(stripslashes($_REQUEST['Nationality']))."','".mysql_real_escape_string(stripslashes($_REQUEST['Province']))."','".mysql_real_escape_string(stripslashes($_REQUEST['DATE1']))."')";

if($result = mysql_query($sql ,$db)) {

echo '<h1>Success!</h1>';

} else {

echo "ERROR: ".mysql_error();

}

} else

?>

 

 

<?php

$DATE1= $_POST['day'] . "-" . $_POST['month'] . "-" . $_POST['year'];

?>

 

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Echo your query before you submit it. Plug it into a raw query line (like from the console or PHPMyAdmin) and see what errors are reported.

 

Chances are there is a problem with your query.

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Echo your query before you submit it. Plug it into a raw query line (like from the console or PHPMyAdmin) and see what errors are reported.

 

Chances are there is a problem with your query.

 

this is already implemented in her code

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yeah, use this

<?php
if (isset($_REQUEST['submit'])) {
$date1= $_POST['day'] . "-" . $_POST['month'] . "-" . $_POST['year'];
$sql = "INSERT INTO $db_table(Country,Nationality,Province,DATE1) values ('".mysql_real_escape_string(stripslashes($_REQUEST['Country']))."','".mysql_real_escape_string(stripslashes($_REQUEST['Nationality']))."','".mysql_real_escape_string(stripslashes($_REQUEST['Province']))."','$date1')";
if($result = mysql_query($sql ,$db)) {
echo '<h1>Success!</h1>';
} else {
echo "ERROR: ".mysql_error();
}
} else 
?>

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While reading your PHP code I noticed alot of silly errors and mistakes, I've corrected everything I could see for you.

 

HTML Page

<html>
<head>
<script type="text/javascript" src="js/jquery-1.5.2.min.js"></script>
<script type="text/javascript" src="js/jquery.validate.min.js"></script>
<script type="text/javascript" src="js/additional-methods.min.js"></script>
</head>
<body>

<form id="signupForm" method="POST" action="processform.php">
  <div>
    <fieldset>
      <legend>Signup Form</legend>
      <label for="Country">*Country:</label>
      <select name="Country">
      <option value="">-----</option>
      <option value="Canada">Canada</option>
      <option value="UK">UK</option>
      <option value="France">France</option></select></div></p>

      <p><label for="Nationality">*Nationality:</label>
      <div><select name="Nationality">
      <option value="">-----</option>
      <option value="Afghanistan">Afghanistan</option>
      <option value="Albania">Albania</option>
      <option value="Algeria">Algeria</option></select></div></p>

      <p><label for="Province">*Province:</label>
      <div><select name="Province">
      <option value="">-----</option>
      <option value="British Columbia">British Columbia</option>
      <option value="Alberta">Alberta</option>
      <option value="Saskatchewan">Saskatchewan</option></select></div></p>
      
      <p><label for="DATE1">*Date:</label>
      <div><select name="day" id="Date1" class="regularfont"><option value="" selected="selected"></option>
      <option value="1">01</option>
      <option value="2">02</option>
      <option value="3">03</option></select>

      <select name="month" id="Date2" class="regularfont"><option value="" selected="selected"></option>
      <option value="1">January</option>
      <option value="2">February</option>
      <option value="3">March</option></select>

      <select name="year" id="Date3" class="regularfont"><option value="" selected="selected"></option>
      <option value="2014">2014</option>
      <option value="2013">2013</option>
      <option value="2012">2012</option></select>
    </fieldset>
  </div>
  <p>
    <div align="center"><input type="submit" name="submit" value="Submit your entry"></div>
  </p>
</form>
<p>

</body>
</html>

 

PHP Processing Page

<?PHP
$hostname = "localhost";
$db_user = "";
$db_password = "";
$database = "";
$db_table = "";
$db = mysql_connect($hostname, $db_user, $db_password);
mysql_select_db($database,$db);


  if(isSet($_POST['submit'])) {
    $country     = mysql_real_escape_string($_POST['Country']);
    $nationality = mysql_real_escape_string($_POST['Nationality']);
    $province    = mysql_real_escape_string($_POST['Province']);
    $date        = $_POST['day'].'-'.$_POST['month'].'-'.$_POST['year'];

    $myQuery = "INSERT INTO {$db_table} (`Country`,`Nationality`,`Province`,`DATE1`) VALUES ('{$country}','{$nationality}','{$province}','{$date}')");

    if(mysql_query($myQuery)) {
      echo 'Record inserted.';
    } else {
      echo 'An error has occurred: '.mysql_error();
    }

  }
?>

 

Try using the above code and tell me how it goes.

 

Regards, PaulRyan.

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fugix it works! thanks for all your help! and thanks PaulRayn for correcting my mistakes, much appreciated! im trying to work on silly part :)

glad I could help, if you have any more problems we'll be here!

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