ridiculous Posted October 11, 2006 Share Posted October 11, 2006 Generally:I have a table of several columns and I want to take a unique piece of data from each row and pass it into another php function for processing. I am trying to keep this data hidden to the viewer. Specifically:My objective is to insert a button into each row of my table below, and pass a variable I call $postid to the file get_job_details.php for processing. I have a feeling the area I have highlighted is wrong in some way, because I am not able to pass the variable to my display function. <code>echo " <td align=left> ".$row['date']." </td> <td align=center><b>".$row['title']." </b> </td> [color=blue]<td align=center> <a href='get_job_details.php'?postid='postid'> <img src='flesh/detailsbutton.jpg' alt='Details'</a></td>[/color] <td align=center> ".$row['location']." </td>"; echo "</tr>";M</code> Quote Link to comment Share on other sites More sharing options...
ridiculous Posted October 11, 2006 Author Share Posted October 11, 2006 please help! Quote Link to comment Share on other sites More sharing options...
ridiculous Posted October 11, 2006 Author Share Posted October 11, 2006 bump Quote Link to comment Share on other sites More sharing options...
mainewoods Posted October 11, 2006 Share Posted October 11, 2006 [code]<td align=center> <a href='get_job_details.php'?postid='postid'> <img src='flesh/detailsbutton.jpg' alt='Details'[/url]</td>[/code]problems:--img tag not terminated with >--no link terminating tag /a--postid should be php variable(needs dollar sign)[code]<a href='get_job_details.php'?postid='$postid'>[/code]the $postid variable would have to be set above by you Quote Link to comment Share on other sites More sharing options...
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