harleydude Posted October 17, 2006 Share Posted October 17, 2006 I am using JPGraph to create some basic line graphs. According to the spec's i have, there can be anywhere from 1 line to 10 lines on a graph at a time depending on the SQL criteria being passed.Now, in JPGraph, you define a line like this (truncated for simplicity):[code]// Create the first line$p1 = new LinePlot($datay1);$p1->SetColor("navy");$graph->Add($p1);[/code]Note that the line is a standard variable name ($p1). To add another line you just rinse and repeat this code. NOW, since the number of lines is arbitrary, is there a way to pass a variable variable to the JPGraph and replace the $p1 with a more usable scoped variable?I was looking for something like:[code]for($i=0;$i<sizeof($chartarray);$i++){ $p=$("p".$i); $$p = new LinePlot($chartarray[$i]); // get list stored in $i position $$p->SetColor("navy"); $graph->Add($$p);}[/code]I just read some on variable variables but am not sure of how they work and this bit odf code is off the top of my head and is not tested. I will play with this some but need to know if the concept works and best way to impliment it.Thanks in advance,HD Quote Link to comment Share on other sites More sharing options...
craygo Posted October 17, 2006 Share Posted October 17, 2006 Try this[code]$p=$("p".$i);[/code]to this[code]$p = "p".$i;[/code]Ray Quote Link to comment Share on other sites More sharing options...
harleydude Posted October 17, 2006 Author Share Posted October 17, 2006 That helps but the chart is blank...I have an array ($dt) with the following data:[code]** > y dataArray( [0] => Array ( [0] => 1.00 [1] => 1.00 [2] => 1.00 [3] => 1.00 [4] => 1.00 ) [1] => Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 1.50 [4] => 1.50 ) [2] => Array ( [0] => 0 [1] => 2.47 [2] => 2.50 [3] => 2.51 [4] => 2.51 )[/code]Here is what I have for each line of the graph:[code]$graph = new Graph(350,250,"auto"); $graph->SetScale("textlin");for($i=0;$i<sizeof($dt);$i++){ $p="p".$i; $$p = new LinePlot($dt[$i]); // get list stored in $i position $graph->Add($$p);} [/code]image outputs empty indicating that jpgraph does not like the data.I have also tried this by setting $i=0 and commenting out the for loop with no success either. JPGraph does not like the $p="p".$i; varaible name.Can anyone offer help or ideas on how to fix the above code snippet? Quote Link to comment Share on other sites More sharing options...
harleydude Posted October 17, 2006 Author Share Posted October 17, 2006 Nevermind, I got it... the technique implied earlier works fine, there was an error in the code (DOH!!)Thanks for the help!! Quote Link to comment Share on other sites More sharing options...
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