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<?php include(" Question


ferdri3
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Hello person who reads this now ;)

 

I work a lot with <?php include("..."); ?> and I never thought beyond the html I put in there.

 

In 1 of the include files I have the set-up of a simple vertical html/css menu and on the right next to it

I have an image. However, not every page on my website needs the same image and I probably will change

a lot of them frequently.

 

Now I was wondering if (and how) I could include a piece of PHP code which does the following:

 

If the web-url is "page1.php" show "image1.png"

If the web-url is "page2.php" show "image2.png"

If the web-url is "page3.php" show "image3.png"

etc.

 

This way I only have to change the "imageX.png" in 1 file.

 

I hope you can help me.

 

Best regards and thanks in advance!

Ferdri3

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seems to me like you will want to store both the page name and the image name in variables, then use an if conditional to compare the values..

 

$x = 1;
$url = "page".$x.".php";
$image = "image".$x.".php";

 

something simple like that.

however there are some questions that need to be answered.

1. how are these included files being generated? Dynamically? if not, you can simply add the right image manually.

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I would use a switch on the basename of the PHP_SELF server var:

 

switch (basename($_SERVER['PHP_SELF'])) {
    case 'page1.php':
        $image = 'image1.png';
        break;
    case 'page2.php':
        $image = 'image2.php';
        break;
    // etc.
}

 

Ensure you include a "default:", or check the $image variable isset before trying to display the image.

 

Edit

 

You could use a method like AyKay47's suggestion - depends on your situation as to what would work best.

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I use a switch too for stuff like that, don't forget a default

 



$url = basename($_SERVER['PHP_SELF']);

switch ($url) 
{
case "/index.php":
$page_title = 'y';
$h1 = 'yy';
$h2 = 'yyy';
$discription = 'yyyy';
$keywords = 'yyyyyy';
break;

default:
$page_title = 'x';
$h1 = 'xxxx';
$h2 = 'x';
$discription = 'x';
$keywords = 'x';
break;
}

 

You can add an image name for a page

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I would use a switch on the basename of the PHP_SELF server var:

 

switch (basename($_SERVER['PHP_SELF'])) {
    case 'page1.php':
        $image = 'image1.png';
        break;
    case 'page2.php':
        $image = 'image2.php';
        break;
    // etc.
}

 

Ensure you include a "default:", or check the $image variable isset before trying to display the image.

 

Edit

 

You could use a method like AyKay47's suggestion - depends on your situation as to what would work best.

yeah, really depends on the situation here and how many pages are to be created..

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Thanks for the fast replies!

 

I've set up a test server:

www.meesterferdi.net/test1.php

www.meesterferdi.net/test2.php

 

This is what I have now:

 

test1.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<!--  START title & keywords & description  -->
<title>Test Homepage</title>
<meta content="keywords" name="keywords" />
<meta content="testing page" name="description" />
<!--  !END! title & keywords & description  -->
<!--  START CSS stylesheetlinks  -->
<link href="css/test.css" rel="stylesheet" type="text/css" />
<!--  !END! CSS stylesheetlinks  -->
</head>
<body style="margin: 0">
<?php include("menu.php"); ?>
</body>
</html>

 

test2.php looks the same.

 

menu.php

<div id="menu">
<ul>
	<li>
		<a href="menu1.php" title="menu1">menu1</a>
	</li>
	<li>
		<a href="menu2.php" title="menu2">menu2</a>
	</li>
	<li>
		<a href="menu3.php" title="menu3">menu3</a>
	</li>
	<li>
		<a href="menu4.php" title="menu4">menu4</a>
	</li>
	<li>
		<a href="test1.php" title="test1">test1</a>
	</li>
	<li>
		<a href="test2.php" title="test2">test2</a>
	</li>
</ul>
</div>
<div id="title_img">
<?php
switch (basename($_SERVER['PHP_SELF'])) {
    case 'test1.php':
        $image = 'images/image1.png';
        break;
    case 'test2.php':
        $image = 'images/image2.png';
        break;
}
?>
</div>

 

test.css

/*  START menu style  */

ul {
    list-style: none;
    margin: 0;
    padding: 0;
}
img {
    border: none;
} 
#menu {
position: relative;
float: left;
    width: 200px;
    margin: 10px;
}
#menu li a {
    height: 32px;
    voice-family: "\"}\""; 
    voice-family: inherit;
    height: 24px;
    text-decoration: none;
}    
#menu li a:link, #menu li a:visited {
font-family:Arial, Helvetica, sans-serif;
    color: #000;
    display: block;
    background:  url(../images/include/menu.gif);
    padding: 8px 0 0 30px;
}
#menu li a:hover {
    color: #2f5bb7;
    background:  url(../images/include/menu.gif) 0 -32px;
    padding: 8px 0 0 30px;
}
/*  !END! menu style  */

#title_img {
position: relative;
width: 670px;
height: 192px;
float: left;
}

 

The menu displays just fine, but the images dont appear.

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The PHP will be gone because it is processed before it hits your browser.

Anyway, in your code you are assigning the image path to a variable but arent doing anything with it :)

switch (basename($_SERVER['PHP_SELF'])) {
    case 'test1.php':
        $image = 'images/image1.png';
        break;
    case 'test2.php':
        $image = 'images/image2.png';
        break;
}
echo '<img src="', $image , '">';

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The PHP will be gone because it is processed before it hits your browser.

Anyway, in your code you are assigning the image path to a variable but arent doing anything with it :)

switch (basename($_SERVER['PHP_SELF'])) {
    case 'test1.php':
        $image = 'images/image1.png';
        break;
    case 'test2.php':
        $image = 'images/image2.png';
        break;
}
echo '<img src="', $image , '">';

 

The echo made it work!

HUGE thanks to all of you!

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The PHP will be gone because it is processed before it hits your browser.

Anyway, in your code you are assigning the image path to a variable but arent doing anything with it :)

switch (basename($_SERVER['PHP_SELF'])) {
    case 'test1.php':
        $image = 'images/image1.png';
        break;
    case 'test2.php':
        $image = 'images/image2.png';
        break;
}
echo '<img src="', $image , '">';

lol... i assumed the img tag was somewhere below the code he gave us..

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for if anyone wants to know, here is the text version:

 

<?php
switch (basename($_SERVER['PHP_SELF'])) {
    case 'index.php':
        $txt = "Line of Text 1";
        break;
    case 'anotherpage.php':
        $txt = "Line of Text 2";
        break;
}
echo '<h2>', $txt ,'</h2>';
?>

 

If you dont want the text to be a header,

 

replace:

echo '<h2>', $txt ,'</h2>';

with:

echo $txt;

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