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using a function inside a loop?


UrbanDweller

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The answer is yes, a few minutes ago I posted this for someone who wanted to simulate the lottery:

$numbers = array();

function draw() {
   return rand(1,59);
}

for ($i=0; sizeof($numbers) < 6; $i++) {
   $new = draw();
   if (in_array($new, $numbers)) {
      $new = draw ();
   } else {
      $numbers[] = $new;       
   }
}

var_dump($numbers);

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Good example, but the trouble with that is if the draw() number exists it will generate another draw() number without verifying if that also exists. Would be better to define the numbers and have them removed from a number map so they cannot possibly re-occur. Of course, there may also be a better way..

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I don't know about better, but this is the way I code things like the example given:

$numbers = array();

function draw() {
   return rand(1,59);
}

while (count($numbers) < 6){
   do {
       $new = draw();
   } while (in_array($new, $numbers));
   $numbers[] = $new;       
}

var_dump($numbers);

 

@UrbanDweller functions don't care where they are called from, they still work the same.  when you call a function the code jumps there, runs through the function, then jumps back to where it was called from at the end/return of the function.

 

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Perhaps just

 

<?php 

$amount = 5;
$numbers = range( 1,100 );
shuffle( $numbers );

$lottery = array_splice( $numbers, 0, $amount );

print_r( $lottery );

?>

 

But this is not what the OP wanted.

 

The answer is yes. Why not try it out rather than asking?

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