How to store file names derived from glob() in variable array

[ankur0101]

Hi,

I want to store files to variable array using glob()

 

like

$files[0] = xyz.txt

$files[1] = pqr.txt

.

.

.

$files[n] = nfile.txt

 

I know how to list files from directory using glob()

 

<?php
foreach (glob("*.txt") as $filename) {
    echo "$filename size " . filesize($filename) . "\n";
}
?>

 

How can I do that ?

 

[Zane]

You mean $files = glob('*txt);

[ankur0101]

No,

What I mean s if there are 3 files, then PHP will first count number of files. (May be using for loop or whatever)

Then at every count it will do $count++ so as to know how many files exist i.e. number of files

 

Then

$files[0] = xyz.txt

$files[1] = pqr.txt

.

.

.

$files[n] = nfile.txt

[scootstah]

$files = array();

foreach (glob("*.txt") as $filename) {
    $files[] = $filename;
}

 

Like that?

 

If you want to count it just do echo count($files);

[trq]

No,

What I mean s if there are 3 files, then PHP will first count number of files. (May be using for loop or whatever)

Then at every count it will do $count++ so as to know how many files exist i.e. number of files

 

Then

$files[0] = xyz.txt

$files[1] = pqr.txt

.

.

.

$files[n] = nfile.txt

 

You shouldn't say "No" without testing. Zane's code does exactly what your example shows us you want.

[ankur0101]

I will try and get back here.

[ankur0101]

Hi,

It worked.

here is my code.

<?php
$files_in_directory = "home/";
$files = array();

foreach (glob($files_in_directory."*.zip") as $filename) {
    $files[] = $filename;
}
$counter = count($files);
echo "<p>$counter</p>";
print_r($files);

for($i=0; $i<$counter; $i++)
{
    echo "<p>$files[$i]</p>";
    }

?>

 

Can I use $files[$i] to upload file using FOR LOOP ?

 

 

[trq]

Can I use $files[$i] to upload file using FOR LOOP ?

 

Upload to where?

[ankur0101]

uploading to amazon s3 using AmazonS3::create_mpu_object()

[ankur0101]

Hi,

Finally I have uploaded files on amazon s3, but problem is my files are in folder home and glod() shows path like

/home/ankur123.zip

 

So problem is it has created folder home on s3 which I dont want.

how can I print only name of file ?

[trq]

basename

[ankur0101]

Hello,

It worked.

 

Thank you.