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Issues displaying one image from 2 tables


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Hello guys,


I'm trying to figure out how to display and image that is located in one table (profile) and make it correspond to a variable on another table (latest_post) to where you echo out the variable from the table(latest_post) and the image from table(profile) appears next to the post.


any how here is my code:


  $query = mysql_fetch_array(mysql_query("SELECT person FROM latest_post AND avatar_img FROM profile WHERE id FROM latest_post = id FROM profile  "));
  echo $query['avatar_img']; 


Also when echoing out the query I only get the name of the image and not the image this is most likely because my image is stored in a different folder right?


Thanks in advance, your help is much appreciated since I'm barely a beginner at php and MySQL.



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Thanks for your reply sasa but that didn't work.


I probable didn't explain my self right. I'll try again.


1. I need from table (latest_post) $post_id,$person and from table (profile) I need $nick,$avatar_img

2. I need $post_id,$person = $nick

3. Finally  echo the avatar_img for that $nick


Thanks again guys.

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Hell again,


I'm still banging my head trying to figure out the problem with my code, I did make some progress on it changing the query but the end result is not what I need. When echoing my query I should see the name of the avatar image but my result is an "S" below is the code I'm using:


  $query = ("SELECT nick, avatar_img, person FROM latest_post, profile WHERE latest_post.person = profile.nick AND profile.nick = profile.avatar_img WHERE profile.avatar_img='$avatar_img'");
   echo $query[$avatar_img];


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