When I rund this part of the script:
$sql13 = "select account_username from paypal_sales where txn_id = '$txn_id'"; $result13 = mysql_query($sql13) or die( mysql_error() ); $del_account_username = mysql_result($result13); echo "Username: $del_account_username";
I get the error:
Warning: Wrong parameter count for mysql_result() in /home/httpd/vhosts/com/
What does that mean? There is a value for account_username in the table paypal_sales where the txn_id in the database is the same as the $txn_id variable in the script.