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Load form dynamically based on a dropdown selection


ranura
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I have 10 tables in my database.

I want load these 10 table names into a drop-down list.

If a user selects a value form the drop-down list, a form should be displayed with related to the table. (form fields should be appropriate table's column headers)

When user fill the form and submitted, data should be saved in the selected table.

 

Give me a code example to do this.

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Access the database and display all table names found.

In the form use the POST method.

 

On the second page after the table has been selected and the first form submitted, use

 

$table = $_POST['Dropdown Value'];
if ($table == 0)
{
Do This
}
elseif ($table == 1)
{
Do This
}

 

etc etc.

 

I know this is not the best way and i have not tested it.

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