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Print database result from out of while loop


thara

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hello... everyone..

 

I have some small problem. It is when Im fetch data from my database and print those in different location.

I have a database to store images and it contain many type of images. Eg. gallery image, comments image, ad image and so on. So now I need to get only images which type is 'ad'.

 

Note: A single user can store only 2 images as ad images. That mean there are two ad images to a particular user.

 

It ok for me. I did it like this.

 

$q = "SELECT image_name FROM images WHERE image_type = 'ad' AND user = $id";
$r = mysqli_query( $dbc, $q );

while ( $row = mysqli_fetch_array( $r, MYSQLI_ASSOC)) {

  $imageName = $row['image_name']; 

  $imageName; // two images contain in this variable. 

}

 

My problem is, can anybody say, is there a way to print those 2 images in different location (in different two DIV ) and out of while loop.

 

Eg: <div class="add1"> image1 </div>

    <div class="add2"> image2 </div>

 

any comments are highly appreciated.

thank you.

 

 

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Presuming each image is in a separate row...

$q = "SELECT image_name FROM images WHERE image_type = 'ad' AND user = '$id'";
$r = mysqli_query( $dbc, $q );

while ( $row = mysqli_fetch_array( $r, MYSQLI_ASSOC)) {
  $imageName[] = $row['image_name']; 
}
$count = count($imageName);
if($count>0) {
  ?>
  <div class="add1"><?php echo $imageName[0]; ?></div>
  <?php
}
if($count>1) {
  ?>
  <div class="add2"><?php echo $imageName[1]; ?></div>
  <?php
}

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thanks for your reply... now its works for me. further I would like to know. is there a way to exchange images between 2 div in particular time period and displaying 2 image with changing?

 

any comments are greatly appreciated.

thank you.

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Yes. I need to display 2 images like this

 

If day is even display image1 in 1st div and image2 in 2nd div.....

 

If day is odd diaplay image1 in 2nd div and image2 in 1st div.....

 

Is there a way to accomplish this task????

 

any comments are greatly appreciated.

 

Thank You

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Some psuedo code...

 

$num = date('d');
if($num&1) {
$odd = TRUE;
} else {
$odd = FALSE;
}

switch $count
case: 2
	if $odd 
		display div 1 image 2
		display div 2 image 1 
	else 
		display div1 image 1
		display div2 image 2
	}
case: 1
		display div1 image 1
}

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