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Hi, I have columns

`First name | last name | nr (individual number) | pref1 (preference1) | pref2 (preference2)| pref3(preference3) | situation | distance | sex`

with 100 records in one table ap

` SELECT DISTINCT nr FROM ap `

First I have to display all records:

```WHERE sex='F' and pref1='1' ORDER BY situation DESC, distance DESC
AND  WHERE (sex='F' and pref2='1' and situation= ' ' ) ORDER BY distance DESC
and WHERE (sex='F' and pref3='1' and situation= ' ' ) ORDER BY distance DESC
LIMIT 4```

Then I would like to join results from:

```WHERE sex='M' and pref1='1' ORDER BY situation DESC, distance DESC
AND WHERE (sex='M' and pref2='1' and situation= ' ' ) ORDER BY distance DESC
AND WHERE (sex='M' and pref3='1' and situation= ' ' ) ORDER BY distance DESC
LIMIT 7```

and then join to all records from:

```WHERE sex='F' and pref1='2' ORDER BY situation DESC, distance DESC
AND WHERE (sex='F' and pref2='2' and situation= ' ' ) ORDER BY distance DESC
AND WHERE (sex='F' and pref3='2' and situation= ' ' ) ORDER BY distance DESC
LIMIT 10```

and so on...

In the results of all I can't have redundancies. It means when in first group of result I get individual number (column "nr") of '2112' it can't be displayed in last one of results.

Is it possible to do?

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If I understand you correctly, what you can do is this:

```SELECT * FROM
( SELECT ... )
UNION ( SELECT ... )
UNION ( SELECT ... )
```

This will give you the unique results from all of the subqueries.

It depends what you mean by "join" though - usually a join in SQL means to match up results based on common data, such as "same name" or "same id number", and put the matching data in the same result row.  Your question sounds like you want to combine the result sets using "union", which basically means "Get these results, and these results, and these results, and return them all".

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• 1 year later...

Can you provide a small sample of data and an example output that you'd like to get from that data? #### Archived

This topic is now archived and is closed to further replies.

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