Searching for a math genius

[Shadowing]

I'm completly lost on how to solve this. The first theory i had didnt work lol

I"m some what decent with trionometry but i just cant figure out how to solve it.

 

Made a picture to show what im trying to do

I need to find the global location of S

which is the bx and by

Really hope someone knows how to do this

 

 

 

[Pikachu2000]

If you have x/y cooordinates of the start and end points, it should be simple pythagorean theorem stuff. Does c² = a² + b² look familiar?

[Shadowing]

its more complicated then that

 

I already did that part of the math

thats what Distance is 1627.88px

 

The problem is figuring out where its at globaly not just where its at between P1 and P2

[Pikachu2000]

So then where does S come from? If you know its origin and endpoint, which it appears you do, it's still the Pythagorean theorem you'd use to figure out the distance.

[Shadowing]

S is traveling from P1 to P2 and its 40 percent there already

I already know the distance its 1627.88. using the Pythagorean theorem like you mentioned

I need to find where S is at right now on the map. I think i need to use Tangent and Cosine to figure it out.

 

 

S is located

Bx ___ by ____

also i need to know the bx by on a global scale not just with in the block

[Pikachu2000]

If you know the distance between P1 and P2, and that distance is 1627.88, and you know S is 40% of that, then the distance traveled is D * 40%, or 1627.88 * 40 / 100.

[Shadowing]

ya i have that figured on the map also

for traveled under s

651.15px

 

that doesnt give me global position though

[Shadowing]

maybe its as simple as grabing 40 percent from P1 bx and by global and P2 bx and by global. going to try that see what results i get

[Shadowing]

Updated my picture showing the global position of P1 and P2

 

[thomasw_lrd]

Since you know where p1 is globally, you should be able to use pythagorean theorem to find where S is right now.

[Shadowing]

The pythagorean theorem  only finds the Hypotenuse of a triangle which is 1 number

and finding 40 percent of that is only giving me the location of where its at on the hypotenuse

that doesnt tell me where S is located on the map

[Shadowing]

adding 40 percent to the P1 global positions "bx" and subtracting 40 percent from P1 global postiion "by" does give me where its at

 

 

for example P1 "bx" is 1000. so add 40 percent which is 1400. which places S at "bx" 1400

 

but if i was going the oppisite direction it would be reversed

subtract 40% to "bx" and add 40% to "by"

 

trying to think writing a statement for that would work.

 

so really this is a geometry problem maybe excluding the trig i used to find distance. I'm going to look up gemetry formulas

[thomasw_lrd]

yeah, I'm lost now.  Good luck.

[Christian F.]

Find the ratio of how many px up it moves for each px laterally. Then it should be quite simple to find the position, especially if you have the distance travelled already.

You can use the positions of P1 and P2 to figure out this ratio, by taking P2-P1 for each X and Y then divide the two results with each other.

[Shadowing]

Thanks responces everyone

 

I got it figured out.

 

You are right christian your way is kinda like how i got it figured out. I dont have to devide anything though

 

xd = P1_bx + ((P2_ bx - P1_bx ) * percent traveled which was 40 percent)

yd = P1_by + ((P2_by - P1_by)  * percent traveled which was 40 percent)

 

 

so filling in the numbers would be

 

bx = 1000 + ((2200 - 1000) * .40)

by = 1700 + ((600 - 1700)  * .40)

 

return

bx = 1480

by = 1260