$op = $_POST['op'];

[cudsuk]

For those not aware , i am just starting out and trying to learn to solve errors by getting hints or tips , not actually looking for you to do it fo rme as such or i will never learn but i appreciate the help

 

I have a old script that is about 7 years out of date i need to update and it is throwing up a error of

 

Notice: Undefined index: op in C:\xampp\htdocs\videos\contact.php on line 8

 

Notice: Undefined variable: status in C:\xampp\htdocs\videos\contact.php on line 74

 

The code is

 

<?php


// Change these two variables to meet your needs.


$myemail = 'whatever@gmail.com';
$subject = 'my site';


$op = $_POST['op'];


if($op == 'contact')
{
$name = stripslashes($_POST[name]);
$email = stripslashes($_POST[email]);
$text = stripslashes($_POST[text]);
$referer = $_POST[referer];
$remote_host = $_SERVER[REMOTE_ADDR];
$server = $_SERVER[sERVER_NAME];
$browser = $_SERVER[HTTP_USER_AGENT];


if(!eregi("^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$",$email))
{
$status = "We're sorry, but you've entered an incorrect email address.<br>";
}
if(!$name)
{
$status .= "Please enter your name.<br>";
}
if(!$text)
{
$status .= "Please enter a message.<br>";
}


if(!$status)
{
$header = "From: $emailrnReply-To: $emailrn";


$message = "
Name: $name
Referer: $referer
Site: $server
Remote Host: $remote_host
Remote Browser: $browser


$text
";


if(mail($myemail, $subject, $message, $header))
{
$status = "Thank you for your Feedback!!<br><br>";
}
else
{
$status = "There was a problem sending your feedback, please try again later.<br><br>";
}


}
else
{
$status .= "<br>Please press <u>back</u> on your browser to resubmit.<br><br>";
}
} 


// Now check the referer page and ensure it's a proper URL


$referer = $_SERVER['HTTP_REFERER'];


if(!preg_match('#^http\:\/\/[a-z0-9-]+.([a-z0-9-]+.)?[a-z]+#i', $referer))
{
unset($referer);
}


?>


<?php print $status; ?>


<form method="post" action="<?php print $_SELF; ?>">
<input type="hidden" name="op" value="contact">
<input type="hidden" name="referer" value="<?php print $referer; ?>">
Name<br><input name="name" size="35" value=""><br>
E-mail address<br><input name="email" size="35" value=""><br>
<br>Message<br><textarea name="text" cols="50" rows="10"></textarea><br><br>
<input type="submit" value="Send message!">
</form>

 

Line 8 is

[/b]
$op = $_POST['op'];

 

line 74

 

<?php print $status; ?>

 

Looking around and reading posts here , op is not used ?

 

it is

if ($_POST[op] ?

 

or use isset ?

 

Can someone please explain how to change it so it works as i am certainly not a coder , but am i on the right track , i believe it is something about an array not being set first or something ?

 

Thanks for the help i appreciate it , i have managed to solve one other problem already by a kind member saying use so and so , but not saying where or how lmao , if i don't do trial and error i am never going to learn , so thanks if you can help out

 

Edit

 

I think i have spotted another error in this , isn't if(!eregi suppose to be if(!preg_match ?

Edited January 7, 2013 by cudsuk

[haku]

In this code:

$op = $_POST['op'];

You are trying to assing the element of the $_POST array that has a key of 'op'. But this key doesn't exist, so you are getting an error.

 

Before trying to use this key, you need to check if it exists:

if(isset($_POST['op'])
{
 $op = $_POST['op'];

 

As a side note, I couldn't help wonder if this thread was somehow related to transexuals

[cudsuk]

lmao , point taken as explained is very old code , at least i was on the right tracks as such , i just needed to see how it looked ,

 

Ha ha i guess above would only apply in china to lady boys lol

 

Damn now getting

 

Parse error: syntax error, unexpected '{' in C:\xampp\htdocs\videos\contact.php on line 9

Edited January 7, 2013 by cudsuk

[cpd]

You clearly copied and pasted the code...

 

Review the parenthesis. As its a very simple problem to solve I'm definitely not posting the answer

Edited January 7, 2013 by cpd

[cudsuk]

HI cpd , yes i did copy and paste but from notepad++ the <br><br>

 

would not be in my code just here as it does that when pop it in code tags

 

Ok i am led to believe as a } bracket or a semi colon is missing , but maybe i am way of the mark , i am a total novice , so a easy mistake for you to spot but over my head , i will do as you suggest and look at the parenthesis and trial and error it , thanks

 

EDIT

ok is due to having a

if($op == 'contact')
{

 

{ but not a } before it yes ? , so i have to discover where to place it to work as one would open the command as such and the other close it ?

 

Sorry for being a total noob , but got to start somewhere

Edited January 7, 2013 by cudsuk

[cudsuk]

Won't let me edit the line above but <br> is there as i believe is uded in html as a line break durrrrrrr , if i put a ) after

if(isset($_POST['op']))

 

it goes to end but since no close as such i get this , i am struggling a bit , please help

 

Parse error: syntax error, unexpected end of file in C:\xampp\htdocs\videos\contact.php on line 87

[cudsuk]

I aploigise for posting again but it won't let me make a edit after i have done so already

 

Ok , after some googling i discover using isset checks if a variable is set , i changed my code with the help of haku's post

 

So mine is now

if (isset($_GET['op']) && $_GET["op"] == "contact")

 

this resolves my error but yet again , i now have a new one

 

Notice: Undefined variable: status in C:\xampp\htdocs\videos\contact.php on line 72

 

that line is

 

<?php print $status; ?>

 

So i am guessing i have to define that as well now ?

 

Can someone just tell me if code i placed is ok , or have i completely messed it up , hence why i get this , or just the fact that the code i am using is so old and needs a major reworks , i am starting to understand i think that all commands can't be null they have to be assigned as such to work , but my knowledge is 0

 

Am i at least on the right track ?

 

I won't post no more until i solve this as don't want to get a warning for posting to much , cheers

[cudsuk]

Ok i think i have solved it

 

I had it as

 

When sending i got a access violation error , so back to the drawing board

 

Discovered yet more variables needed setting

 

My code is now after a lot of work

 

<?php


// Change these two variables to meet your needs.


$myemail = 'myemail@gmail.com';
$subject = 'Change this contact subject';


if (isset($_GET['op']) && $_GET["op"] == "contact")
{
$name = stripslashes($_POST[name]);
$email = stripslashes($_POST[email]);
$text = stripslashes($_POST[text]);
$referrer = $_POST[referer];
$remote_host = $_SERVER[REMOTE_ADDR];
$server = $_SERVER[sERVER_NAME];
$browser = $_SERVER[HTTP_USER_AGENT];


if(!preg_match("^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$",$email))
{
if (!empty($status)) {
$status = "We're sorry, but you've entered an incorrect email address.<br>";
}
}
if(!$name)
{
if (!empty($status)) {
$status .= "Please enter your name.<br>";
}
}
if(!$text)
{
if (!empty($status)) {
$status .= "Please enter a message.<br>";
}
}


if (!empty($status)) {
if(!$status)
{
$header = "From: $emailrnReply-To: $emailrn";

$message = "
Name: $name
Referer: $referer
Site: $server
Remote Host: $remote_host
Remote Browser: $browser

$text
";

if(mail($myemail, $subject, $message, $header))
{
if (!empty($status)) {
$status = "Thank you for your Feedback!!<br><br>";
}
}
else
{
if (!empty($status)) {
$status = "There was a problem sending your feedback, please try again later.<br><br>";
}
}

}
else
{
if (!empty($status)) {
$status .= "Please press <u>back</u> on your browser to resubmit.<br><br>";
}
}
}
}


// Now check the referer page and ensure it's a proper URL


$referer = $_SERVER['HTTP_REFERER'];


if(!preg_match('#^http\:\/\/[a-z0-9-]+.([a-z0-9-]+.)?[a-z]+#i', $referer))
{
unset($referer);
}


?>


<?php if (!empty($status)) {
print $status;
} ?>


<form method="post" action="<?php if (!empty($_SELF)) {
print $_SELF;
} ?>">
<input type="hidden" name="op" value="contact">
<input type="hidden" name="referrer" value="<?php print $referer; ?>">
Name<br><input name="name" size="35" value=""><br>
E-mail address<br><input name="email" size="35" value=""><br>
<br>Message<br><textarea name="text" cols="50" rows="10"></textarea><br><br>
<input type="submit" value="Send message!">
</form>

 

I had to make changes like this for it to work

 

<form method="post" action="<?php if (!empty($_SELF)) {
print $_SELF;
} ?>">

 

Happy now as i have

 

It appears to work as well now , no errors given , just have to log into my email now and see if i have a test post , can someone just check over my code and tell me if see any other errors ?

 

Thanks for the help seems i might be able to do this php thing after all if pointed to the right place to look ?

Edited January 7, 2013 by cudsuk

[Love2c0de]

http://www.php.net

 

This is the official site. There is all the documentation you need and a manual.

 

Hope it helps,

 

Regards,

 

L2c.

Edited January 7, 2013 by Love2c0de

[cudsuk]

Cheers will take a look Love2c0de

 

Just waiting to see if it did indeed send to my email address now , all i have to do is now add my index page to it so it look slike part of the site

 

Can you just skim over the code above see if can spot anything cheers

[Love2c0de]

I'm not the best at debugging php code, but just as a rule of thumb I would stick your $_POST indexes in single quotes.

$_POST['name'];

 

EDIT: I think you do have to explicitly set the double or single quotes and its returning an undefined constant error

 

That's another great debugging tool - var_dump(). Tells you the type and value of a variable and key/values of arrays.

 

hope it helps.

 

Regards,

 

L2c

Edited January 7, 2013 by Love2c0de

[Christian F.]

Doesn't matter if you're using single or double quotes, as long as you're using quotes (and not mixing them for the same index name).

[cudsuk]

cheers guys

 

Well here's one then right off the bat

 

if (isset($_GET['op']) && $_GET["op"] == "contact")

 

Is now just (not sure why they did that , got the code from elsewhere)

 

if (isset($_GET['op']) && $_GET['op'] == "contact")

Edited January 7, 2013 by cudsuk

[Love2c0de]

You can use double or single quotes I think, but you definitely need to use one of them. See my edited code above, I just tested it and it returned an error when I used no quotes whatsoever.

 

Is your error reporting turned on?

 

Regards,

 

L2c.

[cpd]

Thanks for the help seems i might be able to do this php thing after all if pointed to the right place to look ?

 

I salute you for being so persistent - very well done. There are many individuals who give up at the first error but through your persistence you've corrected it and learnt a lot.

[cudsuk]

cheers cpd , but still waiting on my email lmao ,looks like i might need to look at other settings to see why it isn't sending

[Stooney]

This may cause problems:

$header = "From: $emailrnReply-To: $emailrn";

 

It should be:

 

$header = "From: webmaster@example.com \r\n Reply-To: $email \r\n";

[cudsuk]

Stooney thanks so much for this ,, will try it , i thought that was weird and was going to google a answer but you beat me to it , i was just looking on the php website at different letters and stuff and checking what functions they perform

 

Getting there slowly