ScrewLooseSalad Posted April 17, 2013 Share Posted April 17, 2013 My drop down input doesn't pass the value to the next page correctly echo " <select name='NexternalStocker'> <option value='NULL'>Select</option> <option value='NULL'>-----</option>"; while ($row2 = mysql_fetch_assoc($result2)) { echo "<option value='$row2[external_Stocker]'>$row2[external_Stocker]</option>"; } echo " </select>"; Despite the drop down menu item appearing correctly on the page, "$_POST['Nexternal_Stocker'];" won't retrieve anything on the next page... can anyone give me any pointers? Quote Link to comment Share on other sites More sharing options...
Solution mac_gyver Posted April 17, 2013 Solution Share Posted April 17, 2013 the name of your select menu - name='NexternalStocker' isn't the same as what you are using in the php code - $_POST['Nexternal_Stocker] Quote Link to comment Share on other sites More sharing options...
ScrewLooseSalad Posted April 17, 2013 Author Share Posted April 17, 2013 the name of your select menu - name='NexternalStocker' isn't the same as what you are using in the php code - $_POST['Nexternal_Stocker] wow lame, I was certain I had checked that.... Thanks Quote Link to comment Share on other sites More sharing options...
seandisanti Posted April 17, 2013 Share Posted April 17, 2013 Don't forget you can always print_r($_POST) on the receiving page to confirm names and values when you think you have a discrepancy like this. Quote Link to comment Share on other sites More sharing options...
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