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Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean

yoyo

By yoyo
in PHP Coding Help

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yoyo Newbie

yoyo

Posted
Posted

Hi, I am newbie for PHP and MySQL

 

I found this error, please help me.

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Shopping\products.php on line 39

 

Here the full coding:

<?php

    include("includes/db.php");
include("includes/functions.php");
error_reporting (E_ALL ^ E_NOTICE); 
    if($_REQUEST['command']=='add' && $_REQUEST['productid']>0)
     {
        $pid=$_REQUEST['productid'];
        addtocart($pid,1);
        header("location:shoppingcart.php");
        exit(); 
     }
    
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Products</title>
<script language="javascript">
function addtocart(pid){
document.form1.productid.value=pid;
document.form1.command.value='add';
document.form1.submit();
}
</script>
</head>
 
 
<body>
<form name="form1">
<input type="hidden" name="productid" />
    <input type="hidden" name="command" />
</form>
<div align="center">
<h1 align="center">Products</h1>
<table border="0" cellpadding="2px" width="600px">
<?php 
            $result=mysql_query("select * from products");
            while($row=mysql_fetch_array($result)){extract($row);
        ?>
        <tr>
            <td><img src="<?php echo $row['picture']?>" /></td>
            <td>       <b><?php echo $row['name']?></b><br />
                    <?php echo $row['description']?><br />
                    Price:<big style="color:green">
                        RM<?php echo $row['price']?></big><br /><br />
                    <input type="button" value="Add to Cart" onclick="addtocart(<?php echo $row['serial']?>)" />
            </td>
        </tr>
        <tr><td colspan="2"><hr size="1" /></td>
        <?php } ?>
    </table>
</div>
</body>
</html>
 
aysiu Newbie

aysiu

Posted
Posted

Either products isn't a real table, the table is totally empty, or the db.php include at the beginning did not successfully connect you to the database.

 

P.S. From the PHP website:

 

This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should be used.
The extension they're talking about is the one you're using.
yoyo Newbie

yoyo

Posted
  • Author
Posted (edited)

I had amended to this :

 

<?php
include("includes/db.php");
include("includes/functions.php");
error_reporting (E_ALL ^ E_NOTICE); 
if($_REQUEST['command']=='add' && $_REQUEST['productid']>0){
$pid=$_REQUEST['productid'];
addtocart($pid,1);
header("location:shoppingcart.php");
exit();
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Products</title>
<script language="javascript">
function addtocart(pid){
document.form1.productid.value=pid;
document.form1.command.value='add';
document.form1.submit();
}
</script>
</head>
 
 
<body>
<form name="form1">
<input type="hidden" name="productid" />
    <input type="hidden" name="command" />
</form>
<div align="center">
<h1 align="center">Products</h1>
<table border="0" cellpadding="2px" width="600px">
<?
$result=mysql_query("select * from products");
while($row=mysql_fetch_array($result)){
?>
    <tr>
        <td><img src="<?=$row['picture']?>" /></td>
            <td>   <b><?=$row['name']?></b><br />
            <?=$row['description']?><br />
                    Price:<big style="color:green">
                    $<?=$row['price']?></big><br /><br />
                    <input type="button" value="Add to Cart" onclick="addtocart(<?=$row['serial']?>)" />
</td>
</tr>
        <tr><td colspan="2"><hr size="1" /></td>
        <? } ?>
    </table>
</div>
</body>
</html>
 
 
It didn't have error but it still can't display the database in phpMyAdmin... What should I do?
Edited by yoyo
Ch0cu3r Newbie

Ch0cu3r

Posted
Posted (edited)

 

It didn't have error but it still can't display the database in phpMyAdmin... What should I do?

What do you mean by this?

 

Is this addtocart($pid,1); supposed to add the product to the database? What is the code for this php function

Edited by Ch0cu3r
yoyo Newbie

yoyo

Posted
  • Author
Posted

It didn't display the product, because in my database I do insert the data.

 

the function.php code is :

<?
function get_product_name($pid){
$result=mysql_query("select name from products where serial=$pid");
$row=mysql_fetch_array($result);
return $row['name'];
}
function get_price($pid){
$result=mysql_query("select price from products where serial=$pid");
$row=mysql_fetch_array($result);
return $row['price'];
}
function remove_product($pid){
$pid=intval($pid);
$max=count($_SESSION['cart']);
for($i=0;$i<$max;$i++){
if($pid==$_SESSION['cart'][$i]['productid']){
unset($_SESSION['cart'][$i]);
break;
}
}
$_SESSION['cart']=array_values($_SESSION['cart']);
}
function get_order_total(){
$max=count($_SESSION['cart']);
$sum=0;
for($i=0;$i<$max;$i++){
$pid=$_SESSION['cart'][$i]['productid'];
$q=$_SESSION['cart'][$i]['qty'];
$price=get_price($pid);
$sum+=$price*$q;
}
return $sum;
}
function addtocart($pid,$q){
if($pid<1 or $q<1) return;
 
if(is_array($_SESSION['cart'])){
if(product_exists($pid)) return;
$max=count($_SESSION['cart']);
$_SESSION['cart'][$max]['productid']=$pid;
$_SESSION['cart'][$max]['qty']=$q;
}
else{
$_SESSION['cart']=array();
$_SESSION['cart'][0]['productid']=$pid;
$_SESSION['cart'][0]['qty']=$q;
}
}
function product_exists($pid){
$pid=intval($pid);
$max=count($_SESSION['cart']);
$flag=0;
for($i=0;$i<$max;$i++){
if($pid==$_SESSION['cart'][$i]['productid']){
$flag=1;
break;
}
}
return $flag;
}
 
?>
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