Newbie question. Getting the user to pick an option through a keboard key is being ignored

[Valda]

Howdy folks! Please go easy on me, I'm relatively new to programming and still climbing through the basics.

My code is pretty simple. User gotta pick "d" or "w" to deposit or withdraw his fake virtual money, then he picks the amount and the awesomely cool calculation transpires

But it doesn't work. No matter what is being picked the keyboard always goes to the "else" condition (which tells the user "You can only use enter 'w' or 'd'" -- despite the fact I input "d" or "w"). Basically it completely skips my "if" and "else if" statements.

 

I tried putting "d" in quotations, without, with tags, with what not! 

 

So, any clue what is being done wrong here?

 

<?php

$balance=1000;

echo "Welcome to your bank. Your balance is " . $balance . " Which action would you like to take? (w=withdraw, d=deposit) \n" ;

$user=fgets(STDIN);

 

if ($user=="w")

{

echo "How much would you like to withdraw? \n";

(int)$sum=fgets(STDIN);

$balance = $balance-$sum;

echo "Money successfully withdrawn. Your balance now stands at" . $balance . "";

}

 

else if ($user=="d")

{

echo "How much would you like to deposit? \n";

$sum=fgets(STDIN);

$balance = $balance+$sum;

echo "Money successfully deposited. Your balance now stands at" . $balance . "" ; 

}

else

{

echo "You can only use enter 'w' or 'd'";

    }

?>

[Valda]

Two things I wanted to add, first is that I'm running it in Command Prompt

 

Secondly that changing fgets to fgetc allowed me to define $user as string, however it completely skips "(int)$sum=fgets(STDIN);"

 

Why?

[ginerjm]

According to a google search you might try this:

 

$stdin = fopen('php://stdin', 'r');

$response = fgets($stdin);

 

PS - it is NOT completely skipping your if/else statements.  It is logically proceeding through them and coming to a completely anticipated conclusion.

Edited February 9, 2014 by ginerjm