Multiple $_GET not working ?

[Glenskie]

I am trying to set variables with $_GET from the url...

 

caption.php?image=53348b3068f36.jpg&topcaption=sdfas&bottomcaption=asdfadf

 if (isset($_GET['image'])){
            $picture = $_GET['image'];
            $topcaption = $_GET['topcaption'];
            $bottomcaption = $_GET['bottomcaption'];

 

[ginerjm]

So?  What happens?  How do you know you have a problem?  Turn on error checking to see if you any errors.

[Glenskie]

i just goes blank with a broken image... i think its because i set the content type as image/jpeg

[Glenskie]

<?php

error_reporting(E_ALL);

ini_set('display_errors', '1');





      //Set the Content Type

      header('Content-type: image/jpeg');

       if (isset($_GET['image'])){

            $picture = $_GET['image'];

            $topcaption = $_GET['topcaption'];

            $bottomcaption = $_GET['bottomcaption'];



      // Create Image From Existing File

      $jpg_image = imagecreatefromjpeg("../useruploadedphotos/$picture");



      // Allocate A Color For The Text

      $white = imagecolorallocate($jpg_image, 255, 255, 255);



      // Set Path to Font File

      $font_path = 'fonts/Timeless-Bold.ttf';



      // Set Text to Be Printed On Image

      $text = "$topcaption";



      // Print Text On Image

      imagettftext($jpg_image, 25, 0, 75, 300, $white, $font_path, $text);



      imagejpeg($jpg_image, "../photos/$picture");



      imagejpeg($jpg_image, "../useruploadedphotos/$picture");



       imagejpeg($jpg_image);

      // Clear Memory

      imagedestroy($jpg_image);



// header("location: success.php");

}

else{

      die('eror');

}

    ?> 

[ginerjm]

I am not familiar with the graphics functions of php.  I don't see any output in the above script.  Where do you actually send something out to the client?

[Ansego]

 

ginerjm: I am not familiar with the graphics functions of php.  I don't see any output in the above script.  Where do you actually send something out to the client?

 

I am not familiar with the graphics functions of php.  I don't see any output in the above script.  Where do you actually send something out to the client?

 

 

This needs fix (error): - echo your errors as well for debugging.

die('eror');

And add this to the top of your page

<?php
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(E_ALL);
?>

Edited March 28, 2014 by Ansego

[mac_gyver]

at a minimum, you need to move the header('Content-type: image/jpeg'); statement down so that it is right above the        imagejpeg($jpg_image); line. by outputting the header() first, any php or application error messages are treated as part of the binary image data.

 

i also notice that you are saving the image to two different files. if your intent is to save the image, why are you outputting it to the browser using the header(); and imagejpeg($jpg_image); statements?