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Echo .gif in table equal to table number?


ScottWilson
Go to solution Solved by mac_gyver,

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OK I wrote this bit of code

<?
for($i = 0; $i < $row_TableData['TourWins']; $i++) {
echo '<img src="Assets/Medal.gif" />';
}
?>

 

Its meant to be displaying the img src a number of times defined by the number in the 'Tourwins'. so if there's a 2 in the database TourWins then the Medal.gif will echo twice depicting the 2 tourwins but all I keep getting is this: '; } ?>

 

Any ideas

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