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foreach array

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Hi guys,


Having trouble trying to show values from my $friend array. Only the first friend code is being displayed in my output. 

There are several fields in my mysql associated with the $sql.


Any ideas? 



$sql = "SELECT * FROM friends WHERE Code = '$code' OR FriendCode = '$code' AND Status ='A'";
$result = mysqli_query($cxn,$sql)
	or die ("Can't get friends.");

$friend = array();
while($row=mysqli_fetch_array($result)) {
	if($code == $row['FriendCode']) { $friend[] = $row['Code']; }
	elseif($code == $row['Code']) { $friend[] = $row['FriendCode'];
	foreach($friend as $key => $value) {
             echo $value.'<br />';
Edited by unistake
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  • Solution

I would imagine that the query should return results which have "Code" equal to $code and "Status" equal to 'A'...or "FriendCode" equal to $code and "Status" equal to 'A'. If that's the case, you'll want to add parenthesis around Code and FriendCode:


$sql = "SELECT * FROM friends WHERE (Code = '$code' OR FriendCode = '$code') AND Status ='A'";
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