Jump to content

Dynamic Fields js/php to MySql need to submit dynamically to the database


jungle

Recommended Posts

I can not get the values from the javascript add row to go dynamically as a row into MySql only the form values show up as the form below as one row. I made it as an array, but no such luck, I have tried this code around a multitude of ways. I don't know what I am doing wrong, kindly write out the correct way.

 

 

 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 <html xmlns="http://www.w3.org/1999/xhtml">
 <head>
 <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
 <title>Dynamic Fields js/php to MySql need to submit dynamically to the database</title>
 <?php
 require ('database.php');
 ?>
  <script type="text/javascript">
  var counter     =     1;
  var collector     =     "";
 
  function addfields(indx)
  {
   var tbl = document.getElementById('table_id');
   var newtr = document.createElement('tr');
   counter = counter + indx;
 
   newtr.setAttribute('id','tr'+counter);
 
   newtr.innerHTML = '<td><input type="checkbox" name="checkb'+counter+'" id="checkb'+counter+'" value="'+counter+'" onclick="checkme('+counter+')"></td><td><input type="text" name="text1[]"></td><td><textarea name="textarea1[]"></textarea></td>';
 
   tbl.appendChild(newtr);
  }
 
  function checkme(dx)
 {
    collector += dx+",";
 }
 
  function deletetherow(indx)
  {
   var col = collector.split(",");
 
   for (var i = 0; i < col.length; i++)
   {
    var remvelem = document.getElementById('tr'+col);
    var chckbx = document.getElementById("checkb"+col);
    if(remvelem && chckbx.checked)
    {
     var tbl = document.getElementById('table_id');
    tbl.removeChild(remvelem);
   }
   }
  }
 </script>
 </head>
 <body>
 <form enctype="multipart/form-data" id="1" style="background-color:#ffffff;" action="<?php echo $_SERVER['PHP_SELF']; ?>"></form>
 <table id="table_id" >
   <tr id="tr1" class="trmain">
   <td>
   </td>
    <td>
    <input type="text" name="text1[]">
  </td>
    <td>
   <textarea name="textarea1[]"></textarea>
     </td> 
   </tr>
  </table>
 <input type="button" value="Add" onClick="addfields(1);" /> 
 <input type="button" value="Delete" onClick="deletetherow()" />
 <input type="submit" value="Send" id="submit"  name="submit"/>
 
 <?php
 if(isset($_POST['submit'])) {
 for ($i=0; $i < count($_POST['text1']); $i++ )
 {
 $ced = stripslashes($_POST['text1'][$i]);
 $erg = stripslashes($_POST['textarea1'][$i]);
 }
 
 
 $bnt = mysql_query("INSERT INTO tablename (first, second) VALUES ('$ced', '$erg')")or die('Error: '. mysql_error() );
 $result = mysql_query($bnt);
 }
 
 ?>
 
 </body>
 </html>

Link to comment
Share on other sites

Because you only tell it to insert 2 values:

$bnt = mysql_query("INSERT INTO tablename (first, second) VALUES ('$ced', '$erg')")or die('Error: '. mysql_error() );
$result = mysql_query($bnt);

That should probably be in your loop where you are retrieving $ced and $erg from $_POST.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.