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Sending individual JSON variables back to php


MargateSteve
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I have been banging my head against a wall for a few days over this and think that I have read so many alternative ways, I have got myself confused!
 
What I am trying to do is post some information into the database and on success, provide certain variables back to my script (for example last_insert_id) as I would like to show a success message an add an option to a select on that page.
 
I am trying to get this part working without the mysql first just so I understand it. Currently I can post the data, have that received successfully in the processing page (addDetail.php) and send back output from that page........
 
insert.php 

$("#sub").click(function() {
  var name = $("#name").val();
  var town = $("#town").val();
        
  jQuery.ajax({
    type: "POST",
    url: "postScripts/addDetail.php",
   
    data: 'name='+name+'&town='+town,
    
    success: function(html) {

      $(".modal-body").prepend(
          "Returned: " +html
        );
    }
  });
  return false
}) 

addDetail.php


$name = $_POST['name'];
$town = $_POST['town'];
 
//Check $_POST data
echo "<pre>"; print_r($_POST) ;  echo "</pre>";
 
$return["name"] = $name;
$return["town"] = $town;

echo json_encode($return); 

 
 Result in insert.php

Returned:
Array
(
    [name] => The Name
    [town] => The Town
)
{"name":"The Name","town":"The Town"}

This works fine to bring back everything on the processing page in one go but I want to bring back separated variables so I can use them individually. I thought that changing 

 "Returned: " +html

to

 "Returned: " +html.name

would allow me to bring back just that variable but it comes back undefined. This is the closest I have got as other methods I tried either brought nothing back or just [objectObject]. 

 

How would I be able to bring back both 'name' and 'town' as separated values so I can use them individually in my script?

 

Thanks in advance

 

Steve

Edited by MargateSteve
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Personally I would call $return something else, for that is close to using a reserve word that's just me:

// In your JQuery 
$("#sub").click(function() {
  var name = $("#name").val();
  var town = $("#town").val();
        
  jQuery.ajax({
    type: "POST",
    url: "postScripts/addDetail.php",
   
    data: 'name='+name+'&town='+town,
    
    success: function(info) {
     var name = info.name,
         town = info.town;

     /* Continue with code */  
    }
  });
  return false
}) 

Edited by Strider64
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  • 3 weeks later...

You should only respond with pure JSON (otherwise jQuery will get confused) and also tell jQuery to expect JSON back using the data type parameter of the ajax request function.
 


$("#sub").click(function() {

  var name = $("#name").val();

  var town = $("#town").val();



  jQuery.ajax({

    type: "POST",

    url: "postScripts/addDetail.php",

    data: { name: name, town: town },
    dataType: 'json',
 
    success: function(data) {
      $('.modal-body').prepend('Returned: ' + data.name + ' and ' + data.town);
      $('.modal-body').prepend('Whole post: ' + data.whole_post);
    }
  });

});

$json = array();


$json['name'] = $_POST['name'];

$json['town'] = $_POST['town'];



$json['whole_post'] = var_export($_POST, true);
 
echo json_encode($json);
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