AzeS Posted July 28, 2016 Share Posted July 28, 2016 (edited) Title says it all... I tried it this way: <?php $THROWOUT_PAYED_FULL = number_format((float)$BUYEDFULL, 2, '.', $BUYEDHALF); echo $THROWOUT_PAYED_FULL; #echo's 1.0 #goal is: 1.1 ?> Any suggestions ? Edited July 28, 2016 by AzeS Quote Link to comment Share on other sites More sharing options...
requinix Posted July 28, 2016 Share Posted July 28, 2016 Try $THROWOUT_PAYED_FULL = (float)($BUYEDFULL . '.' . $BUYEDHALF); Quote Link to comment Share on other sites More sharing options...
AzeS Posted July 28, 2016 Author Share Posted July 28, 2016 echo's two.. doesnt work Quote Link to comment Share on other sites More sharing options...
requinix Posted July 28, 2016 Share Posted July 28, 2016 Does too. https://3v4l.org/v5Cdt Quote Link to comment Share on other sites More sharing options...
Solution Barand Posted July 28, 2016 Solution Share Posted July 28, 2016 As this is a math help forum $x=1; $y=1; $z = $x + $y/10; echo $z; Quote Link to comment Share on other sites More sharing options...
Barand Posted July 28, 2016 Share Posted July 28, 2016 More generalized case $x=1; $y=111; $z = $x + $y/pow(10,strlen($y)); Quote Link to comment Share on other sites More sharing options...
AzeS Posted July 28, 2016 Author Share Posted July 28, 2016 Solved thanks alot !! Quote Link to comment Share on other sites More sharing options...
AzeS Posted July 28, 2016 Author Share Posted July 28, 2016 <?php $BUYEDFULL = 1000; $BUYEDHALF = 120; for ($i=0; $i < $BUYEDHALF; $i++) { if($i = 100 ) { $BUYEDFULL++; $BUYEDHALF = $BUYEDHALF - 100; $i = 0; } } $x=$BUYEDFULL; $y=$BUYEDHALF; $z = $x + $y/100; echo "<br>".$z; ?> Quote Link to comment Share on other sites More sharing options...
requinix Posted July 28, 2016 Share Posted July 28, 2016 Quote Link to comment Share on other sites More sharing options...
AzeS Posted July 29, 2016 Author Share Posted July 29, 2016 Quote Link to comment Share on other sites More sharing options...
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