PHP Fatal error: Call to a member function prepare() on null

[bbmak 0]

Hi

Trying to implement with the prepare statement, and it gives me this error.

"PHP Fatal error:  Call to a member function prepare() on null."

Anybody knows what is wrong? 

	function listMerchant() {
		
		$merchant = array();
		
		$merchantList = $this->mysqli->prepare("SELECT * FROM core_merchant");
		$merchantList->execute();
		while($merchantRows = $merchantList->fetch_array()) {
			
			$merchant[] = $merchantRows;
			
		}
		
		$merchantList->close();
		
		return $merchant;
		
	}

[Jacques1 628]

It means there's no such thing as $this->mysqli. Either that attribute doesn't even exist, or you've failed to assign a connection to it.

[bbmak 0]

ummm.... I have other functions in the class using  $this->mysqli-query(), and they work fine. Somehow the prepare() is not working. I am new to prepare(), and not sure my syntax is correct or not. 

Edited March 1, 2017 by bbmak

[bbmak 0]

I go back and check my connection. The file include the wrong path for the connection folder. I fixed that, and now I got this.

PHP Fatal error: Call to undefined method mysqli_stmt::fetch_array()

[Jacques1 628]

A prepared statement doesn't have a fetch_array() method. Read the manual on how prepared statements work.

 

Actually, you don't need this at all, because you have no external input. The entire method can be boiled down to

function listMerchant() {
    return $this->mysqli->query('SELECT col1, col2, ... FROM core_merchant')->fetch_all(MYSQLI_BOTH);
}

Edited March 1, 2017 by Jacques1

[bbmak 0]

Thank you guru.