How to show div based on specific URL in PHP (if statement)?

[kenjisi]

How to show div based on specific URL in PHP (if statement)?

 

For example, we have these URL:

http://www.abc.com/about/

http://www.abc.com/background/

http://www.abc.com/contact/

 

Show this div for http://www.abc.com/about/

<div>This is About</div>

 

This div for http://www.abc.com/background/

<div>This is Background</div>

 

This div for http://www.abc.com/contact/

<div>This is Contact</div>

[benanamen]

Rather than crowd your page with a bunch of unrelated information you can use includes to display the relevant information. Optimally, you want a single point of entry to your site, index.php and then include the relevant pages based on the URL. Without pretty URL's: index.php?p=about,  index.php?p=contact, etc...

 

You're allowed pages should be whitelisted in an array so users cannot try to randomly include pages. There is code on the forum from @Jaques1 that will show you how to do this. 

[kenjisi]

Thanks Benanamen! For some reasons (not technical) my access not allow me to use includes but i need to make this things happen. Are there any code similar like this to get things works:

<?php

    if(xxxx..http://www.abc.com/about/){

        echo '<div>contents</div>';

    }

?>

 

Sorry if i asking something stupid, Im new to php.

[benanamen]

You might be thinking of server-side includes. PHP includes is a standard part of PHP. Look it up in the manual.