qwe Posted August 20, 2017 Share Posted August 20, 2017 i'am working on file upload so i have to add things on it like adding file name generation as in the pic > http://prntscr.com/gaoko3 make the image appears before uploading to check if you want to or change other one make the direct link appears after the image uploading done as in the pic > http://prntscr.com/gaokvr filename generation something like 98bzcx.png , .gif etc my code <!doctype html> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <body> <title>birdupload: upload</title> </body> </head> <meta name="description" content="upload your image today"> <meta name="twitter:site" content="@"> <meta charset='UTF-8'/> <meta http-equiv="Pragma" content="no-cache"/> <meta http-equiv="Expires" content="0"/> <nav><a href="gallery.php">gallery</a> | home</nav> <h3> <img src="/images/logo.png"> </h3> <!-- stylesheet --> <!-- /stylesheet --> <link rel="shortcut icon" href="favicon.ico"> <form action="upload.php" method="post" enctype="multipart/form-data"> browse: <input type="file" name="image"><br/><br/> <input type="submit" name="upload" value="continue"> </form> <ul> <li>sent file name: <?php echo $_FILES['image']['name']; ?> <li>file size: <?php echo $_FILES['image']['size']; ?> <li>file type: <?php echo $_FILES['image']['type'] ?> </ul> <?php if(isset($_POST['upload'])){ $image_name = md5($_FILES['image']['name']); $image_type = $_FILES['image']['type']; $image_size = $_FILES['image']['size']; $image_tmp_name= $_FILES['image']['tmp_name']; @$desc = $_POST['desc']; $allowed=array("image/jpeg", "image/gif", "image/png"); if(!in_array($image_type,$allowed)) echo "only jpg, gif, and png files are allowed."; else{ move_uploaded_file($image_tmp_name,"uploads/$image_name"); echo "<img src='uploads/$image_name' width='350' height='250'><br>"; echo "your image:"; } } ?> Link to comment Share on other sites More sharing options...
ginerjm Posted August 20, 2017 Share Posted August 20, 2017 And the question/problem is??? Link to comment Share on other sites More sharing options...
qwe Posted August 20, 2017 Author Share Posted August 20, 2017 And the question/problem is??? how can i make them Link to comment Share on other sites More sharing options...
ginerjm Posted August 20, 2017 Share Posted August 20, 2017 OH! You're looking for programming skills for hire? There is another forum for that. Here we help people who are having difficulty with their code. Code that they have written. Programming is all about having a problem to solve. Designing a possible solution. Developing the code for that. And testing that it does what you need. And repeat. My suggestion - choose one problem and work on it. If you have a very specific piece that you can't find a solution for (implying that you tried!) then show us what you have and ask a clear question on how to improve/fix it. Don't just come here with your grandiose plans and hope that someone is going to jump up and write a hundred lines of code for you. Link to comment Share on other sites More sharing options...
qwe Posted August 20, 2017 Author Share Posted August 20, 2017 OH! You're looking for programming skills for hire? There is another forum for that. Here we help people who are having difficulty with their code. Code that they have written. Programming is all about having a problem to solve. Designing a possible solution. Developing the code for that. And testing that it does what you need. And repeat. My suggestion - choose one problem and work on it. If you have a very specific piece that you can't find a solution for (implying that you tried!) then show us what you have and ask a clear question on how to improve/fix it. Don't just come here with your grandiose plans and hope that someone is going to jump up and write a hundred lines of code for you. i try to display the image with this code . <?php if(isset($_POST['upload'])){ $image_name = md5($_FILES['image']['name']); $image_type = $_FILES['image']['type']; $image_size = $_FILES['image']['size']; $image_tmp_name= $_FILES['image']['tmp_name']; @$desc = $_POST['desc']; $allowed=array("image/jpeg", "image/gif", "image/png"); if(!in_array($image_type,$allowed)) echo "only jpg, gif, and png files are allowed."; else{ move_uploaded_file($image_tmp_name,"uploads/$image_name"); echo "<img src='uploads/$image_name' width='350' height='250'><br>"; echo "your image:"; $image=$_FILES["file"]["name"];$img="upload/".$image; echo '<img src= "upload/".$img>'; } } ?> and it won't work ie: appears the image before uploading it i try to mix this code with my main code upload.php and won't work Link to comment Share on other sites More sharing options...
ginerjm Posted August 20, 2017 Share Posted August 20, 2017 You need to read your code with a closer eye. Try echo-ing out what you built as a "image name" and you'll see what you did. PS - when you get the image name properly built, check the server to be sure that the name you are trying to access does in fact exist. PS - is the image located within the web-accessible tree? Link to comment Share on other sites More sharing options...
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