PHP floor count of array elements

[Adaaam]

Hi all,

 

I have an array of elements which is dynamically set but for testing purposes I have this code:

<?php 

$items = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32);
$count = floor(count($items));

var_dump($count);

This returns float(32) but I want to know why it doesn't return the rounded down value of 30? I must be missing something or misunderstanding the function but if someone could explain why this is happening and how I can fix it then that would be great

 

Thanks,

Adam

 

[Barand]

Have you tried the manual?

count

floor

[Adaaam]

Yes I've tried the manual, maybe you can explain?

[requinix]

I'm confused. Why should floor(32) be 30?

[Adaaam]

Doesn't the function round down?

[Barand]

What, in this description of the floor() function,

Returns the next lowest integer value (as float) by rounding down value if necessary.

leads you to think floor(32) will return 30?

[Adaaam]

Okay fine can you tell me if there is a different function I can use to round 32 to 30 or 49 to 40 or 56 to 50 or 114 to 110? I'm asking for help here...

[Barand]

try

echo round(32, -1);  //-->30

edit: However round(39) = 40, so you will need

 

floor(N/10) * 10

[requinix]

That will round, so 35->40.

echo round(32 - 5, -1);

Maps 30-39 to 25-34.

[Barand]

See my edited version

[Adaaam]

Alright sorted, thanks.

[kicken]

Also:

 

$n - ($n % 10)

Take your pick, several ways to do it.

[requinix]

Hmm. What other ways could there be...

substr($n, 0, -1) . "0"

...is all I've got. I'll keep thinking.