php getting min values index

[Paola]

<?php

$a = array(-15, 3, 5, -1, -15);
$b = array(1, 3, 5);

function lowest_int ($c){

 
   print_r(array_keys($c, min($c)));
    
    

   }

print_r(lowest_int($a));
print_r(lowest_int($b));

?>

Hello guys the out of my code should be [0] => -15 [4] => -15 for the first array and [0] => 1 for the second array.
However. this is my output:

 

Array ( [0] => 1 [1] => 4 )

Array ( [0] => 0 )

 

Any ideas what am doing wrong? Thank you so much in advance!

Edited June 5, 2019 by Paola

[Barand]

Have your function return the keys instead of printing them, then print the function results

function lowest_int ($c){
   return array_keys($c, min($c));
}

 

[Paola]

Thank you for your input. I still get the same result.

[Barand]

Having got the keys with the min value you then need to get those items from the original array

$a = array(-15, 3, 5, -1, -15);
$b = array(1, 3, 5);

function lowest_int ($c){
    $result = [];
    foreach (array_keys($c, min($c)) as $k) {
            $result[$k] = $c[$k];
    }
    return $result;    
}          

echo '<pre>';
print_r(lowest_int($a));
print_r(lowest_int($b));
echo '</pre>';

output

Array
(
    [0] => -15
    [4] => -15
)
Array
(
    [0] => 1
)

An alternative solution could be to use array_filter() in your function to remove items not equal to the minimum value

function lowest_int ($c){
      $min = min($c);
      return array_filter( $c, function($v) use($min) { return $v==$min; } );
}          

 

[Paola]

Thank you so much. That fixed my issue. I still want to research why my results were so off and with new number =(

 

Thank you again ?