Jump to content
Huongle08

get this error code

Recommended Posts

Fairly new to PHP and have the following code which should simply output into 3 columns - I have checked the query which does work - so I dont understand why I get this error

mysql_fetch_array() expects parameter 1 to be resource,

 

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}

$sql = “SELECT * FROM duration_matched WHERE groupm = '”.$coincidence ."’";
$result = $conn->query($sql);

// set up loop counter
$col_count = 0;

// start table and first tr
echo ‘

’;

while ($row=mysql_fetch_array($result)) {
// if you have output 3 cols then end tr and start a new one
if ($col_count == 3) {
echo ‘

’;
// and reset the col count
$col_count = 0;
}

// always output the td
echo ‘

’;
// and count the column
$col_count++;
}

// then close off the last row and the table
echo ‘

’ . $row[‘image’] . ‘

’;

$conn->close();

Share this post


Link to post
Share on other sites

Also note that you created (correctly) a mysqli connection but you have switched to a mysql_ library function that is now obsolete

Share this post


Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.


×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.